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3 years ago

How do you factor a trinomial into two binomials?

Mathematics

1 answer:

hjlf3 years ago

3 0

Answer: Formula For Factoring Trinomials (when a =1)

It's always easaier to understand a new concept by looking at a

specific example so you might want to do that first. This formula works

when 'a' is 1. [ In other words, we will use this approach whenever the

coefficient in from of x2 is 1.

1) identify a,b, and c in the trinomial ax2 + bx+c

2) write down all factor pairs of c

3) identify which factor pair from the previous step sums up to b

4) Substitute factor pairs into two binomials

Step-by-step explanation:

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Step-by-step explanation:

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Determine if each pair of ratios forms a proportion. Show all work! 7/C = 35/60

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Answer

C = 12

Explanation

Ratio is a division. For the two ratios to be proportional, then they must be the same after been simplified to their simplest form.

7/C = 35/60

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3 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

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Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

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