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satela [25.4K]
3 years ago
14

1b. True or False? Explain your answer without multiplying. 2 points

Mathematics
2 answers:
VladimirAG [237]3 years ago
5 0

False

How?

Let 5x^2-2x+6 be A

The expression will be

\\ \sf\longmapsto A(2x-3)=A(3x-2)

\\ \sf\longmapsto 2x-3=3x-2

But it's impossible

\\ \sf\longmapsto 2x-3\neq 3x-2

natita [175]3 years ago
3 0

Answer:

  • False

Step-by-step explanation:

<h2>Solution 1</h2>

The easy way is to compare the leading terms or constants.

<h3>LHS</h3>

<u>The leading term is:</u>

  • 2x*5x² = 10x³

<u>The constant is:</u>

  • (-3)*6 = -18
<h3>RHS</h3>

<u>The leading term is:</u>

  • 3x*5x² = 15x³

<u>The constant is:</u>

  • (-2)*6 = -12

We see both the leading terms (10x³ ≠ 15x³) and constants (-18 ≠ -12) are different so the equation is false.

<h2>Solution 2</h2>

<u>We see one of the factors is same on both sides: </u>

  • 5x² - 2x + 6

<u>The other factors are:</u>

  • 2x - 3 = 3x - 2

Since this factor is different on both sides, the equation is false

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How to solve this inequality: 3p - 6 &gt; 21.
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3 years ago
Three roots of a fifth degree polynomial function f(x) are -2,2 and 4 + i which statement describes the number and nature of all
liubo4ka [24]

Answer:

f(x) has three real roots and two imaginary roots.

Step-by-step explanation:

Given that three roots of a fifth degree polynomial function f(x) are -2,2 and (4+i).

Now we need to find about which of the given statements describes the number and nature of all roots for this function.

We know that imaginary roots always occur in conjugate pairs.

So if (4+i) is root then (4-i) must also be the root.

So now we have total 4 roots

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Degree of the polynomial is 5 so that means 1 root is still remaining. It can't be imaginary as that must be in pairs

So that means 5th root is real.

Hence correct choice is :

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4 years ago
Write a two point slope equations for the line passing through the points 6,5 and 3,1
Gwar [14]

The 2-point form of the equation of a line can be written as ...

... y = (y2-y1)/(x2-x1)·(x -x1) +y1

For your points, this is ...

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It can also be written as

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