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3 years ago

2y+4=5x-4= Help please

Mathematics

2 answers:

IgorLugansk [536]3 years ago

7 0

Answer:

x = 2 and y = 1.

Step-by-step explanation:

If in the given quadrilateral all angles ∠A, ∠B, ∠C, ∠D are 90°and opposite sides are equal, then this property of a quadrilateral concludes that the given quadrilateral is a rectangle.

5x - 4 = 2y + 4

5x - 2y = 4+4 =8--------(1)

and 5y + 1 = 3x

3x - 5y = 1--------(2)

We multiply equation 1 by 3 and equation 2 by 5

15x - 6y = 24------(3)

15x - 25y = 5------(4)

Now we subtract equation 4 from 3

15x - 6y - (15x - 25 y) = 24-5

15x -6y -15x + 25y =19

19y = 19

y = 1

By putting y = 1 in equation 1.

5x - 2 = 8

5x = 10

x = 2

timofeeve [1]3 years ago

5 0

Answer:

2y+4 is equal to 5x-4.

5y+1 is equal to 3x.

Step-by-step explanation:

2y+4=5x-4=

According to the properties of a quadrilateral, the parallel or the opposite sides of the figure are equal. Hence, in this figure, the lengths from A to B will be equal to the length from D to C and the lengths from A to D will be equal to the length from B to C.

Therefore, in such a case 2y+4 is equal to 5x-4.

Likewise, 5y+1 is equal to 3x.

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Write the standard equation of the circle with center (– 10, –3) that passes through the point (-3,3).

Sphinxa [80]

Answer:

$(x+10)^2 + (y+3)^2 = 85$

Step-by-step explanation:

Equation of a circle:

The standard equation of a circle with center $(x_0,y_0)$ is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In which r is the radius.

Center (– 10, –3)

This means that $x_0 = -10, y_0 = -3$ . So

$(x - x_0)^2 + (y - y_0)^2 = r^2$

$(x - (-10))^2 + (y - (-3))^2 = r^2$

$(x+10)^2 + (y+3)^2 = r^2$

Passes through the point (-3,3).

This means that we use $x = -3, y = 3$ to find the radius squared. So

$(x+10)^2 + (y+3)^2 = r^2$

$(-3+10)^2 + (3+3)^2 = r^2$

$r^2 = 49 + 36$

$r^2 = 85$

The equation of the circle is:

$(x+10)^2 + (y+3)^2 = r^2$

$(x+10)^2 + (y+3)^2 = 85$

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3 years ago

A cage holds two litter of rats. One litter comprises one female and five males. The other litter comprises seven females and tw

timurjin [86]

Answer:

The probability that the two rats are from the first litter is 14.28%, and the probability that the two rats are from the second litter is 34.28%.

Step-by-step explanation:

Since a cage holds two litter of rats, and one litter comprises one female and five males, while the other litter comprises seven females and two males, and a random selection of two rats is done, to find the probability that the two rats are from the same litter the following calculation must be performed:

6/15 x 5/14 = 0.1428

9/15 x 8/14 = 0.3428

Therefore, the probability that the two rats are from the first litter is 14.28%, and the probability that the two rats are from the second litter is 34.28%.

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Answer:

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Step-by-step explanation:

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