I do not believe so but dont quote me on it.
Answer:
Vertex: (3, 23)
Step-by-step explanation:
a = -1 b = 6 c = 14
x vertex = 
Answer:
x³/4z²
Step-by-step explanation:
Invert and multiply:
48x^5y²/12z^5 x z³/16x²y²=
(48x^5y²)(z³)/(16x²y²)(12z^5)
the y² cancel out
48÷16=3 (on top)
x^5÷x²=x³
12z^5/z³=z²(on bottom)
This leaves a 3x³ on top and 12z² on the bottom. 3÷12=4 (on bottom):
3x³/12z²
x³/4z²
Answer:
-1+5z, -25+20y, 4d+14, 2n-2, 40k+8, 8b+5, -9+22p
Step-by-step explanation:
1) -4+7z+3-2z
-1+5z
2) 15+4(5y-10)
15+20y-40
-25+20y
3) 2d+17-3-2d+4d
4d+14
4) 12n-8-2n+10-4
2n-2
5) 8(2k+1+3k)
16k+8+24k
40k+8
5) 4(2b+2)-3
8b+8-3
8b+5
6) -4+8p-6p-5+20p
-9+22p
B. First off , standard form of a 2nd degree equation is Ax^2 + Bx + C. So look at the coefficient of Ax^2 which is -2.
If positive, the parabola opens up and has a minimum.
If negative, the parabola opens down and has a maximum.
A. To find the vertex (in this case maximum),
Graph the equation -OR—
make a table. — OR—
Find the zeroes and find the middle x-value
-2x^2 - 4x + 6
-2(x^2 +2x - 3 = 0
-2 (x - 1) ( x + 3)=0
x - 1 = 0. x + 3 = 0
x = 1. x = -3. So halfway would be at (-1, __).
Sub in -1 into original equation -2x^2 -4x + 6 … -2(-1)^2 -4(-1) + 6 = -2 +4 +6 = 8
So the vertex is (-1,8)
