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2 years ago

May someone please help me

Mathematics

1 answer:

fiasKO [112]2 years ago

8 0

a. equate yourequation to zero then yourx intercepts are (-6;0) and (4;0)

b. to find the y-intercept...let x=0...where there is x put 0 and your answer is -24 therefore the y-intercept is (0;-24)

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Sarah makes 5 ribbons the first day. On the second day she doubles the number of

sdas [7]

20 ribbons

Explanation:
1st day— 5 ribbons
2nd day—2 x 5 = 10 ribbbns
3rd day— 2 x 10 = 20

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2 years ago

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Are they right??? <br><br> Due tomorrow

DedPeter [7]

Yes they are right you did a great job!

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2 years ago

Find each measure plz help

Rashid [163]

Answer:

m∠QRS = 52°

Step-by-step explanation:

From the given figure,

In right triangles ΔRQT and ΔRST,

QT = TS = 7.5 units [Given]

RT ≅ RT [Reflexive property]

ΔRQT ≅ ΔRST [By HL theorem of congruence]

Therefore, m(∠QRT) = m(∠SRT) = 26° [CPCTC]

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4 0

2 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

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2 years ago

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Ipatiy [6.2K]

$5_{(paint\ colors)}\ \cdot\ 6_{(beds)} \ \cdot\ 5_{(dressers)}=150_{(chooses)} \\\\Ans.\ 150\ chooses.$

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2 years ago

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