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Nostrana [21]
3 years ago
5

Dan has 4 groups of 10 and 3 left over.

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0
Is there anything else? Like what is the question asking?
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How to solve this in steps?
gtnhenbr [62]

4a + 5 = 3(a - 7) + 2a
4a + 5 = 3a - 21 + 2a
4a + 5 = 5a -21
4a -5a = -21 -5
-a = -26
a = 26

3 0
3 years ago
Read 2 more answers
The following equation f(x) = x³ + 0.5x² + 4.5 has only 1 real root. It lies between the interval [-1,0].
Mrac [35]

Answer:

I believe that a=the answer is C if It's not then probably A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How do you solve (6,-7)(3,-5)
Masteriza [31]

are u looking for the slope?

5 0
3 years ago
If y varies inversely as x and y = 9 when x = 4, find y when x = 6.
Rudiy27

Answer: x

=

6

Explanation:

the initial statement is

x

∝

1

y

to convert to an equation multiply by k the constant

of variation

⇒

x

=

k

×

1

y

=

k

y

to find k use the given condition

x

=

4

when

y

=

9

x

=

k

y

⇒

k

=

x

y

=

4

×

9

=

36

equation is

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

x

=

36

y

2

2

∣

∣

∣

−−−−−−−−−−−−

when

y

=

6

then

x

=

36

6

=

6

Step-by-step explanation:

3 0
3 years ago
Consider the following equations. f(x) = − 4/ x3, y = 0, x = −2, x = −1. Sketch the region bounded by the graphs of the equation
Sindrei [870]

Answer:

1.5 unit^2

Step-by-step explanation:

Solution:-

- A graphing utility was used to plot the following equations:

                         f ( x ) = - \frac{4}{x^3}\\\\y = 0 , x = -1 , x = -2

- The plot is given in the document attached.

- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).

- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.

We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).

The double integration formulation can be written as:

                           A= \int\limits_c^d \int\limits_a^b {} \, dy.dx \\\\A = \int\limits_c^d { - \frac{4}{x^3} } . dx\\\\A = \frac{2}{x^2} |\limits_-_2^-^1\\\\A = \frac{2}{1} - \frac{2}{4} \\\\A = \frac{3}{2} unit^2

Answer: 1.5 unit^2 is the amount of area bounded by the given curve f ( x ) and the boundary equations.

Download docx
3 0
3 years ago
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