Answer:
20 years
Step-by-step explanation:
20 is the lowest common multiple of 5,4,2
Answer:
8x
15
y
9
Step-by-step explanation:
Answer:
$0.05
Step-by-step explanation:
1.25/25=0.05
Answer:
$46,141.71
Step-by-step explanation:
This looks about right, based on weekly deposits for the duration. However, I cannot vouch for it entirely, as the number of weekly deposits in 15 years will actually be 782.
_____
Computing this by hand doing the initial balance separately from the weekly deposits, I get a total of $46,252.10 using 782 weekly deposits. For that purpose, I tried to figure an equivalent weekly interest rate given monthly compounding and the fact there are 52 5/28 weeks in a year on average.
I suspect the only way to get this to the cent would be to build a spreadsheet with payment dates and interest computation/payment dates. Some months, there would be 5 deposits between interest computations; some years there would be 53 deposits.
Answer:
- Solution of equation ( q ) = <u>1</u><u>6</u>
Step-by-step explanation:
In this question we have given an equation that is <u>3 </u><u>(</u><u> </u><u>q </u><u>-</u><u> </u><u>7</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u>and we have asked to solve this equation that means to find the value of <u> </u><u>q</u><u> </u><u>.</u>
<u>Solution : -</u>

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis :

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 21 on both sides :

On further calculations we get :

<u>Step </u><u>3 </u><u>:</u> Dividing by 3 from both sides :

On further calculations we get :

- <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>equation</u><u> </u><u>(</u><u> </u><u>q </u><u>)</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>.</u>
<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>
Now we are very our answer by substituting value of q in the given equation . So ,
<u>Therefore</u><u>,</u><u> </u><u>our </u><u>solution</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u>
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<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>