3 years ago

What is 1.2 simplified

Mathematics

1 answer:

natali 33 [55]3 years ago

5 0

Answer:

it is 1 2/10 but simplified to 1 1/5

Step-by-step explanation:

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Write an expression that shows how to multiply 7 x 256 using expanded form and the distributive property

natali 33 [55]

256×7=1792 in expanded form it is 1000+700+90+2

6 0

3 years ago

Read 2 more answers

Each packet of the cooking oil weighs 2/5th of a kilogram and one kilogram of the cooking oil costs $6.5. Sara went to the groce

Reika [66]

Answer:

C) $20.80

Step-by-step explanation:

1 kg of cooking oil = $6.5

1 packet of cooking oil =2/5 kg

If 1 kg of cooking oil = $6.5

2/5kg of cooking oil = $X

Cross Multiply

1kg × $X = 2/5kg × $6.5

$X = 13/5

$X = 2.6

Hence 2/5kg of oil cost $2.6

Since 1 packet of oil = 2/5kg of oil , 1 packet of oil cost $2.6

The amount she spent if she bought if she bought 8 packets of the cooking oil is calculated as:

1 packet of oil = $2.6

8 packets of oil =

$2.5 × 8

= $20.80

Therefore,if Sara bought 8 packets of oil, the amount she would spend = $20.80

7 0

3 years ago

I need help please help me

oksian1 [2.3K]

Answer:

d=2

Step-by-step explanation:

6 0

3 years ago

1a. Alex skateboards at a constant speed from his house to school 4 miles away. It takes him 15 minutes. What fraction represent

erastovalidia [21]

Minutes - 15/4
or
Seconds - 15/240

3 0

2 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

3 years ago