8.888194417 to one decimal place first one gets brainlist

What is the slope of the line with the equation of y= 3x that passes through the points (2, 6)?

SashulF [63]

Answer:

is there a picture?

Step-by-step explanation:

5 0

3 years ago

A circle has a diameter of 12 feet. What is the circumference of the circle?

Lady bird [3.3K]

Answer:

B). 37.68 feet.

Step-by-step explanation:

Circumference = diameter * π

= 12 * π

= 37.68 feet.

5 0

3 years ago

The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough

liberstina [14]

Answer:

a) $t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

$\bar X=1175$ represent the sample mean for the cubic feets of households

$\sigma=250$ represent the population standard deviation

$n=100$ sample size

$\mu_o =1425$ represent the value to verify

$\alpha=0.025$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:

Null hypothesis: $\mu \geq 1425$

Alternative hypothesis: $\mu < 1425$

Since we don't know the deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0

3 years ago

ok so this is drag and drop so tell me which answer goes in each box the for the box o the left count that as the first box ty n

Ainat [17]

Answer:

$\Huge\boxed{z$

Step-by-step explanation:

Hello There!

Once again we need to isolate the variable using inverse operations

to get rid of the -8.2 we add 8.2 to each side

-8.2+8.2 cancels out

-9.7+8.2=-1.5

now we have

-1.2z>-1.5

now we wan to get rid of the -1.2

to do so we want to divide each side by -1.2

$\frac{-1.2z}{-1.2} =z\\\\\frac{-1.5}{-1.2} =1.25$

Remember we have to flip the inequality sign because we're dividing by a negative number

we're left with

z<1.25

7 0

3 years ago

Read 2 more answers

Heather drew the scaled drawing of a train car shown below. She used the scale of 2 cm = 5 ft to complete the

lora16 [44]

Answer: c

Step-by-step explanation:

3 0

3 years ago