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Nastasia [14]
3 years ago
9

Find the midpoint of the following segment created by these pairs of endpoints: (0, 1), (0, 5)

Mathematics
2 answers:
Anettt [7]3 years ago
7 0
<span>3: (0, 3)
The mid point is the value in the middle of the two end points.</span>
lyudmila [28]3 years ago
4 0
I believe it is 1, but i'm not completely sure.
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This probability distribution shows the typical grade distribution for a Geometry course with 35 students . A B С DF Grade Frequ
Nataly [62]

Answer:

p=0.29

Step-by-step explanation:

Total ~ of ~students=35

Probability =10/35=0.29

<u>----------------------------</u>

hope it helps....

have a great day!!

4 0
3 years ago
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Please help, I will give brainliest.
kotegsom [21]

Answer:

b = 30 / a

which agrees with the third expression in the list of possible options

Step-by-step explanation:

When we say that a and b vary inversely, that means that in mathematical form:

b = k / a  where "k" is the so called "constant of proportionality". In order to write the function that models this inverse variation, we need to find the value of "k". We do such by using the information they provide (b = 5/2 when a = 12):

5/2 = k / 12

Then, solving for "k":

5 * 12 / 2 = k

60 / 2 = k

k = 30

Then we can now write the function that models this inverse variation:

b = k / a

b = 30 / a

5 0
3 years ago
I’m confused help please
Ad libitum [116K]

Answer:

The first one maybe or thrid one

Step-by-step explanation:

5 0
3 years ago
A conjecture and the flowchart proof used to prove the conjecture are shown.
amm1812

Answer:

∠1 + ∠2 + ∠3 = 180°

Step-by-step explanation:

Given :  AB II XC

To Show : ∠1 + ∠2 + ∠3 = 180°

Proof: Here, given that AB is parallel to the line XC

⇒  ∠4  =  ∠2  (Pair of Alternate angles as AB II XC)  .........  (1)

and ∠5  =  ∠3 (Pair of Alternate angles as AB II XC) ...........  (2)

Now, ∠1 + ∠4 + ∠5  = 180° ( Straight Angle)

But, from above (1) and (2)

∠1 + ∠2 + ∠3   =   180°  ( as ∠4  =  ∠2,  ∠5  =  ∠3)

Hence, ∠1 + ∠2 + ∠3   =   180°

Hence Proved.

7 0
3 years ago
Multiply the polynomials (y −5)(2y+ 3)
ollegr [7]

Answer:

(-3 + -2y)(5 + -1y) = 0

Step-by-step explanation:

Simplifying

(y + -5)(2y + 3) = 0

Reorder the terms:

(-5 + y)(2y + 3) = 0

Reorder the terms:

(-5 + y)(3 + 2y) = 0

Multiply (-5 + y) * (3 + 2y)

(-5(3 + 2y) + y(3 + 2y)) = 0

((3 * -5 + 2y * -5) + y(3 + 2y)) = 0

((-15 + -10y) + y(3 + 2y)) = 0

(-15 + -10y + (3 * y + 2y * y)) = 0

(-15 + -10y + (3y + 2y2)) = 0

Combine like terms: -10y + 3y = -7y

(-15 + -7y + 2y2) = 0

Solving

-15 + -7y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.

(-3 + -2y)(5 + -1y) = 0

6 0
3 years ago
Read 2 more answers
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