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lisov135 [29]
3 years ago
6

Suponha que uma variável assume os valores: 11 – 8 – 7 – a – 16 – 10 Determine a de modo que a média aritmética seja igual 11.

Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

a = 14  

Step-by-step explanation:

The mean is the sum of the values divided by the number of values.

\begin{array}{rcl}\text{Mean}&= &\dfrac{11 + 8 + 7 + a + 16 + 10}{6}\\\\\dfrac{52 + a}{6}& = & 11\\52 + a & = & 66\\a & = & 66 - 52\\& = & \mathbf{14}\\\end{array}

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At a football game three out of the first five student that arrived were wearing a jacket based on his information if 300 studen
WARRIOR [948]

Answer:

120 students students could be expected to not be wearing a jacket

Step-by-step explanation:

Based on this, we can work with the assumption that 3/5 of the students that entered the stadium were wearing jackets.

Given that the total population of students that attended the game is 300

This means that 3/5 of the 300 = 180 students.

180 students were estimated to be wearing jackets.

The number of students that were without jackets is 300 - 180 = 120 students

7 0
3 years ago
Evaluate the exponential expression (−2)6. Question 6 options: −12 12 −64 64
OlgaM077 [116]

Answer:

64

Step-by-step explanation:

(-2) ^6

This is -2 multiplied by itself 6 times

-2 * -2 *-2 * -2* -2 *-2

64

7 0
3 years ago
A population of values has a normal distribution with μ=204.9μ=204.9 and σ=81.9σ=81.9. You intend to draw a random sample of siz
marin [14]

Answer:

7. μ=204.9 and σ=5.4968

8. μ=75.9 and σ=0.7136

9. p=0.9452

Step-by-step explanation:

7. - Given that the population mean =204.9 and the standard deviation is 81.90 and the sample size n=222.

-The sample mean,\mu_xis calculated as:

\mu_x=\mu=204.9, \mu_x=sample \ mean

-The standard deviation,\sigma_x is calculated as:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{81.9}{\sqrt{222}}\\\\=5.4968

8. For a random variable X.

-Given a X's population mean is 75.9, standard deviation is 9.6 and a sample size of 181

-#The sample mean,\mu_x is calculated as:

\mu_x=\mu\\\\=75.9

#The sample standard deviation is calculated as follows:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{9.6}{\sqrt{181}}\\\\=0.7136

9. Given the population mean, μ=135.7 and σ=88 and n=59

#We calculate the sample mean;

\mu_x=\mu=135.7

#Sample standard deviation:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{88}{\sqrt{59}}\\\\=11.4566

#The sample size, n=59 is at least 30, so we apply Central Limit Theorem:

P(\bar X>117.4)=P(Z>\frac{117.4-\mu_{\bar x}}{\sigma_x})\\\\=P(Z>\frac{117.4-135.7}{11.4566})\\\\=P(Z>-1.5973)\\\\=1-0.05480 \\\\=0.9452

Hence, the probability of a random sample's mean being greater than 117.4 is 0.9452

7 0
3 years ago
When 12 is decreased by twice a number, the result is -14. Find the number.
Talja [164]

Answer:

-13

Step-by-step explanation:

Twice a number is 2h (h is the variable) so the equation is 12-2h=-14 and - 13 times 2 is -26 so the equation is now 12-26=-14

4 0
3 years ago
On Monday it rained two and one-half inches. On Tuesday it rained three and three-fourths inches. How much did it rain in the tw
charle [14.2K]

Answer:

it rained 6 1/4 or 6.25 inches in two days

3 0
3 years ago
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