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2 years ago

PLEASE HELP

Mathematics

2 answers:

denpristay [2]2 years ago

6 0

the statement must be true

D. <A+<D=180°

galben [10]2 years ago

5 0

Answer:

b c = 180

Step-by-step explanation:

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The sum of two numbers is 53 and the difference is 11. What are the numbers ?

eimsori [14]

The numbers are 32 and 21
32 + 21 = 53
32 - 21 = 11

7 0

2 years ago

Simplify enter your answer

ioda

Answer: 5/14

Explanation:
19-14=5

3 0

2 years ago

Cameron wants to measure a poster frame, but he only has a sheet of paper that is 8 1/2 b 11 inches

Nataly [62]

Long side is 11 inches
4 times 11=44 inches
that is 44 inches

5 0

2 years ago

Read 2 more answers

Please help me with this

denis23 [38]

Answer:

20) $\displaystyle [4, 1]$

19) $\displaystyle [-5, 1]$

18) $\displaystyle [3, 2]$

17) $\displaystyle [-2, 1]$

16) $\displaystyle [7, 6]$

15) $\displaystyle [-3, 2]$

14) $\displaystyle [-3, -2]$

13) $\displaystyle NO\:SOLUTION$

12) $\displaystyle [-4, -1]$

11) $\displaystyle [7, -2]$

Step-by-step explanation:

20) {−2x - y = −9

{5x - 2y = 18

⅖[5x - 2y = 18]

{−2x - y = −9

{2x - ⅘y = 7⅕ >> New Equation

__________

$\displaystyle \frac{-1\frac{4}{5}y}{-1\frac{4}{5}} = \frac{-1\frac{4}{5}}{-1\frac{4}{5}}$

$\displaystyle y = 1$ [Plug this back into both equations above to get the x-coordinate of 4]; $\displaystyle 4 = x$

_______________________________________________

19) {−5x - 8y = 17

{2x - 7y = −17

−⅞[−5x - 8y = 17]

{4⅜x + 7y = −14⅞ >> New Equation

{2x - 7y = −17

_____________

$\displaystyle \frac{6\frac{3}{8}x}{6\frac{3}{8}} = \frac{-31\frac{7}{8}}{6\frac{3}{8}}$

$\displaystyle x = -5$ [Plug this back into both equations above to get the y-coordinate of 1]; $\displaystyle 1 = y$

_______________________________________________

18) {−2x + 6y = 6

{−7x + 8y = −5

−¾[−7x + 8y = −5]

{−2x + 6y = 6

{5¼x - 6y = 3¾ >> New Equation

____________

$\displaystyle \frac{3\frac{1}{4}x}{3\frac{1}{4}} = \frac{9\frac{3}{4}}{3\frac{1}{4}}$

$\displaystyle x = 3$ [Plug this back into both equations above to get the y-coordinate of 2]; $\displaystyle 2 = y$

_______________________________________________

17) {−3x - 4y = 2

{3x + 3y = −3

__________

$\displaystyle \frac{-y}{-1} = \frac{-1}{-1}$

$\displaystyle y = 1$ [Plug this back into both equations above to get the x-coordinate of −2]; $\displaystyle -2 = x$

_______________________________________________

16) {2x + y = 20

{6x - 5y = 12

−⅓[6x - 5y = 12]

{2x + y = 20

{−2x + 1⅔y = −4 >> New Equation

____________

$\displaystyle \frac{2\frac{2}{3}y}{2\frac{2}{3}} = \frac{16}{2\frac{2}{3}}$

$\displaystyle y = 6$ [Plug this back into both equations above to get the x-coordinate of 7]; $\displaystyle 7 = x$

_______________________________________________

15) {6x + 6y = −6

{5x + y = −13

−⅚[6x + 6y = −6]

{−5x - 5y = 5 >> New Equation

{5x + y = −13

_________

$\displaystyle \frac{-4y}{-4} = \frac{-8}{-4}$

$\displaystyle y = 2$ [Plug this back into both equations above to get the x-coordinate of −3]; $\displaystyle -3 = x$

_______________________________________________

14) {−3x + 3y = 3

{−5x + y = 13

−⅓[−3x + 3y = 3]

{x - y = −1 >> New Equation

{−5x + y = 13

_________

$\displaystyle \frac{-4x}{-4} = \frac{12}{-4}$

$\displaystyle x = -3$ [Plug this back into both equations above to get the y-coordinate of −2]; $\displaystyle -2 = y$

_______________________________________________

13) {−3x + 3y = 4

{−x + y = 3

−⅓[−3x + 3y = 4]

{x - y = −1⅓ >> New Equation

{−x + y = 3

________

$\displaystyle 1\frac{2}{3} ≠ 0; NO\:SOLUTION$

_______________________________________________

12) {−3x - 8y = 20

{−5x + y = 19

⅛[−3x - 8y = 20]

{−⅜x - y = 2½ >> New Equation

{−5x + y = 19

__________

$\displaystyle \frac{-5\frac{3}{8}x}{-5\frac{3}{8}} = \frac{21\frac{1}{2}}{-5\frac{3}{8}}$

$\displaystyle x = -4$ [Plug this back into both equations above to get the y-coordinate of −1]; $\displaystyle -1 = y$

_______________________________________________

11) {x + 3y = 1

{−3x - 3y = −15

___________

$\displaystyle \frac{-2x}{-2} = \frac{-14}{-2}$

$\displaystyle x = 7$ [Plug this back into both equations above to get the y-coordinate of −2]; $\displaystyle -2 = y$

I am delighted to assist you anytime my friend!

7 0

2 years ago

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m2, and the area of circle

taurus [48]

Solution:

we are given that

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.

we have been asked to find the ratio of the radius of circle Q to the radius of circle R?

As we know that

Area of the sector is directly proportional to square of radius. So we can write

$Area \ \ \alpha \ \ r^2\\ \\ \Rightarrow A=kr^2\\ \\ \text{where k is some proportionality constant }\\ \\ \Rightarrow \frac{A_1}{A_2}=\frac{r_1^2}{r_2^2}\\ \\ \Rightarrow \frac{r_1^2}{r_2^2}=\frac{A_1}{A_2}\\ \\ \Rightarrow \frac{r_1^2}{r_2^2}=\frac{25 \pi}{49 \pi}\\ \\ \Rightarrow \frac{r_1}{r_2}=\sqrt{\frac{25 \pi}{49 \pi}} \\ \\ \Rightarrow \frac{r_1}{r_2}=\frac{5}{7} \\$

7 0

2 years ago

Read 2 more answers