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3 years ago

A right triangle has leg lengths 8 and x. The hypotenuse length is (x + 2). What is the length of the hypotenuse?

Mathematics

1 answer:

umka2103 [35]3 years ago

4 0

Answer:

17 is the length of the hypotenuse.

Step-by-step explanation:

The pythagora theorem tells us a²+b²=c², where C is hypotenuse.

Replace the given info into the formula:

8² + x² = (x+2)²

64 + x² = x² + 4x + 4

64 - 4 = 4x

60 = 4x

x = 60/4

x = 15

Hypotenuse length is 15+2=17

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Which is bigger, 7/8" or 9/16"?

Iteru [2.4K]

7/8 and 9/16

7*2/8*2 = 14/16

14/16 and 9/16

Now since we have a common denominator, we can compare the numerators.

14/16 is greater, so 7/8 is greater than 9/16

Answer: 7/8 is bigger

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3 years ago

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Solve for x in the figure below

fredd [130]

Answer:

x = 35.4

Step-by-step explanation:

Sum of all interior angles in a triangle = 180°

Therefore:

(x + 2)° + (2x + 2)° + (2x - 1)° = 180°

x + 2 + 2x + 2 + 2x - 1 = 180

Collect like terms

x + 2x + 2x + 2 + 2 - 1 = 180

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5x/5 = 177/5

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: ( $a = 1$ , $b = -1$ , $c = 4$ )

$D = b^{2}-4\cdot a\cdot c$

$D = (-1)-4\cdot (1)\cdot (4)$

$D = -17$ (Conjugated complex roots)

Step E

$(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0$

Step F

$x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936$

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How do you multiply fractions with a whole number

Allisa [31]

You put the whole number on top of 1, it doesnt change its value. then you simplify across like in a butterfly only if needed then you multiply across from left to right.

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