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Andru [333]
3 years ago
12

Angles X and Y form a straight line. Angles W and Z form a straight line. Angles X and W are beside each other. Angles Y and Z a

re beside each other. Which equation represents the relationship of the measure of m∠X and m∠Y? m∠X = m∠Y m∠X + m∠Y = 90° m∠X + m∠Y = 100° m∠X + m∠Y = 180°
Mathematics
2 answers:
Zanzabum3 years ago
5 0

Answer:

a

Step-by-step explanation:

VikaD [51]3 years ago
4 0

Answer:The answer to this question is D

Step-by-step explanation:

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kvv77 [185]
It’s gonna be 1/125.

Since it’s F(3), you need to plug the 3 into the x. Then expand it into 1/5 times 1/5 times 1/5, which gets you 1/125
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Hi i need help with 15a(ii)
Art [367]

Answer:

x = 5/2

Step-by-step explanation:

log4(x^2+5x)-log8(x^3)=1/log3(4)

log(x^2 + 5 x) / log(4) - log(x^3) / log(8) = log(3) / log(4)

log(x (x+5))/log(4) - log(x^3) / log(8) = log(3) / log(4)

(3 log(x (x+5)) - 2 log(x^3)) / log(64) = log(3) / log(4)

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Solve the equation by finding square roots. x2-1/4=0
Serjik [45]

Answer:

x = ±1/2

Step-by-step explanation:

x^2-1/4=0

Add 1/4 to each side

x^2 -1/4+1/4 = 0+1/4

x^2 = 1/4

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sqrt(x^2) = sqrt(1/4)

x = ±1/2

6 0
3 years ago
COME ON PEOPLE I REALLY NEED THE ANSWER
tamaranim1 [39]
The answer is number 3
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3 years ago
A random sample of 100 teletype operators indicates that their salaries fluctuate quite a bit. The sample Standard deviation of
ELEN [110]

Answer:

\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}

80.341 \leq \sigma^2 \leq 128.495

Now we just take square root on both sides of the interval and we got:

8.963 \leq \sigma \leq 11.336

Step-by-step explanation:

Data given and notation

s=10 represent the sample standard deviation

\bar x represent the sample mean

n=100 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=100-1=99

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,99)" "=CHISQ.INV(0.95,99)". so for this case the critical values are:

\chi^2_{\alpha/2}=123.225

\chi^2_{1- \alpha/2}=77.046

And replacing into the formula for the interval we got:

\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}

80.341 \leq \sigma^2 \leq 128.495

Now we just take square root on both sides of the interval and we got:

8.963 \leq \sigma \leq 11.336

5 0
3 years ago
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