3x - y = 9
y = -2x + 11
3x - (-2x + 11) = 9
3x + 2x - 11 = 9
3x + 2x = 9 + 11
5x = 20
x = 20/5
x = 4
y = -2x + 11
y = -2(4) + 11
y = -8 + 11
y = 3
solution (where the lines intersect) is (4,3)
Answer:
Step-by-step explanation:
Tổng : -7,5+(-3,6)+(-4,7)+(-5,3)+(-1,4)=-22,5
W + L = 122
W = 3L + 14
3L + 14 + L = 122
4L + 14 = 122
4L = 122 - 14
4L = 108
L = 108/4
L = 27 <=== they lost 27 games
W = 3L + 14
W = 3(27) + 14
W = 81 + 14
W = 95 <=== they won 95 games
Answer:
The correct answer is: 3x² (4x - 1) / (x - 4) (x - 3) ∧ restriction x ≠ 3, x ≠ 4, x ≠ 0 and x ≠ 1/4
Step-by-step explanation:
Given:
((16x² - 8x + 1) / (x² - 7x + 12)) : ((20x² - 5x) / 15x³) =
dividing with one fraction is the same as multiplying with its reciprocal value
((16x² - 8x + 1) / (x² - 7x + 12)) · (15x³ / (20x² - 5x))
First we need to factorize both numerators and denominators
16x² - 8x + 1 = (4x - 1)² This is square binomial
x² - 7x + 12 = x² - 4x - 3x + 12 = x (x - 4) - 3 (x - 4) = (x - 4) ( x - 3)
20x² - 5x = 5x (4x - 1)
(4x - 1)² / (x - 4) (x - 3) · 15x³ / 5x (4x - 1)
The existence of this rational algebraic expression is possible only if it is:
x - 4 ≠ 0 and x - 3 ≠ 0 and x ≠ 0 and 4x - 1 ≠ 0 =>
x ≠ 4 and x ≠ 3 and x ≠ 0 and x ≠ 1/4 This is restriction
Finally we have:
3 x² (4x - 1) / (x - 4) (x - 3)
God with you!!!
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