You would solve this with simultaneous equations, so if we write it as:
5n + 2p = 9
3n + 2p = 6
(subtract)
2n = 3
÷ 2
notebooks = 1.5
Now you would substitute it in:
(3 × 1.5) + 2p = 6
4.5 + 2p = 6
- 4.5
2p = 1.5
÷ 2
pens = 0.75
So your final answer is notebooks are $1.50 and pens are $0.75, I hope this helps!
Answer:
Therefore Josiah must sell 68 or 69 or 70 tacos in order to meet the requirement.
Step-by-step explanation:
Given , Josiah owns a food truck that sells tacos and burritos.
He sells each burritos for $7.50. If 79 burritos were sold.
Then the price of 79 burritos is $(7.50×79) =$592.50
Let x tacos were sold.
He sells each tacos for $5.
Then the price of x tacos is = $(x × 5)=$5x
Also given that Josiah must sell a minimum of $930 worth of tacos and burritos.
Therefore,
5x+592.50≥ 930
⇔5x≥930-592.50
⇔5x≥337.5
⇔x≥67.5
But he only has enough supplies to make 149 tacos or burrito.
He already sold 79 burrito.
So, remain space for tacos is = (149-79) = 70
So,67.5≤x≤70
∴x = 68 or 69 or 70
Therefore Josiah must sell 68 or 69 or 70 tacos in order to meet the requirement.
Step-by-step explanation:
the two A's in the buttom is correct
