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lakkis [162]
3 years ago
13

A human blinks 9,460,800 times per year. A dog blinks 1,861,440 times per year. About how many more times does a human blink tha

n a dog?
A. 2
B. 8
C. 10
D. 5
Sorry, I can't change the number of points you get.
Please answer this fast I need it!
Mathematics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:

The answer is D.

Step-by-step explanation:

In order to find how many times human blink more than the blink of a dig, you have to divide it :

9460800 \div 1861440

= 5 \: times

Ray Of Light [21]3 years ago
6 0
5 times you just have to divide the two numbers
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Which two number have an absolute value of 2
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Answer:2 -2

Step-by-step explanation:absolute value is distance from zero so both of those are the same distance from zero

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3 years ago
If two angles are vertical and one of the angles is 2x+10 and the other is 70 degrees.find the value of x
weqwewe [10]

Answer:

  x = 30

Step-by-step explanation:

Vertical angles have equal measures, so ...

  2x +10 = 70

  2x = 60 . . . . . . subtract 10

  x = 30 . . . . . . . divide by 2

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3 years ago
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Three times a number is equal to 12 less than the number. Find the number.​
Juliette [100K]
Well (three times four is equal to twelve. So the answer should be 4
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3 years ago
A manufacturer considers his production process to be out of control when defects exceed 3%. In a random sample of 100 items, th
pochemuha

Answer:

The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.

Step-by-step explanation:

A manufacturer considers his production process to be out of control when defects exceed 3%.

At the null hypothesis, we test if the production process is in control, that is, the defective proportion is of 3% or less. So

H_0: p \leq 0.03

At the alternate hypothesis, we test if the production process is out of control, that is, the defective proportion exceeds 3%. So

H_1: p > 0.03

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.03 is tested at the null hypothesis

This means that \mu = 0.03, \sigma = \sqrt{0.03*0.97}

In a random sample of 100 items, the defect rate is 4%.

This means that n = 100, X = 0.04

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.04 - 0.03}{\frac{\sqrt{0.03*0.97}}{\sqrt{100}}}

z = 0.59

P-value of the test

The p-value of the test is the probability of finding a sample proportion above 0.04, which is 1 subtracted by the p-value of z = 0.59.

Looking at the z-table, z = 0.59 has a p-value of 0.7224

1 - 0.7224 = 0.2776

The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.

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2 years ago
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Answer:

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Hope this helps!

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