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Studentka2010 [4]
3 years ago
8

What is the probability of randomly selecting a day of the week and not getting Monday?

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
6 0

Days in a week n(S)=7

DAYS to not getting monday n(M)=6

probability P(M)=n(M)/n(S)

=6/7(ans)

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A temperature recorded in antarctica was 121 f . the temperature recorded in the sahara desert was 133 f. how many degrees warm
weeeeeb [17]
131+121=252 degrees...........................
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3 years ago
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15 POINTS!!!! BRAINLIEST FOR THE FIRST ANSWER!!! Solve 3-x/2≤18
Bumek [7]

Answer:

x\geq -30

Step-by-step explanation:

Work to isolate x on one side of the inequality:

3-\frac{x}{2} \leq 18\\3-18\leq \frac{x}{2} \\-15\leq  \frac{x}{2}\\-30 \leq x

Therefore the answer is all x values larger than or equal to -30

x\geq -30

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I can't figure out how to do (i + j) x (i x j)for vector calc
Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}

Then, solving the determinant

\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}

In our case,

\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}

Where we used the formula for AxB to calculate ixj.

Finally,

\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}

Thus, (i+j)x(ixj)=i-j

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