Answer:
#3: x is approximately 0.37, -5.37, #4: x is approximately 4.19, -1.19
Step-by-step explanation:
You can solve using the quadratic equation or by solving with the perfect square
= 
x is approximately 0.37, -5.37
Answer:
<h3>2</h3>
Step-by-step explanation:
The value of pi is 22/7
Expressing as a decimal, the first ten digits of pi is 3.1415926535
The value in the tenth digit of the pi is 5 (tenth value after the decimal point)
The value of the ones is 3(The value before the decimal point)
The difference between both values = 5 - 3
The difference between both values = 2
Hence the difference of the ones and the tenth digit of the pi is 2
Answer:

Step-by-step explanation:
In order to find an equation of a line with two given ordered pairs. We have to find a slope first which we can do by using the formula below.

m-term is defined as slope in y = mx+b form which is slope-intercept form.
Now we substitute these ordered pairs (x, y) in the formula.

After we calculate for slope, we substitute m-value in slope-intercept form. The slope-intercept form is

We already know m-value as we substitute it.

We are not done yet because we need to find the b-term which is our y-intercept. (Note that m-term is slope while b-term is y-intercept)
We can find the y-intercept by substituting either (-14,1) or (13,-2) in the equation. I will be using (13,-2) to substitute in the equation.

Finally, we know b-value. Then we substitute it in our equation.

Answer:
![6 \sqrt[3]{5}](https://tex.z-dn.net/?f=6%20%5Csqrt%5B3%5D%7B5%7D)
Step-by-step explanation:
For the problem,
, use rules for simplifying cube roots. Under the operations of multiplication and division, if the roots have the same index (here it is 3) you can combine them.
![\sqrt[3]{24} *\sqrt[3]{45} = \sqrt[3]{24*45}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%2A%5Csqrt%5B3%5D%7B45%7D%20%3D%20%5Csqrt%5B3%5D%7B24%2A45%7D)
You can multiply it out completely, however to simplify after you'll need to pull out perfect cubes. Factor 24 and 45 into any perfect cube factors which multiply to each number. If none are there, then prime factors will do. You can group factors together such as 3*3*3 which is 27 and a perfect cube.
![\sqrt[3]{24*45} =\sqrt[3]{3*8*5*3*3} = 6 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%2A45%7D%20%3D%5Csqrt%5B3%5D%7B3%2A8%2A5%2A3%2A3%7D%20%20%3D%206%20%5Csqrt%5B3%5D%7B5%7D)