Question

Please help guys! Find the zeros of the quadratic equation by factoring. x^2+4x-5=0

Answer 1

Answer:

x = -5, 1

Step-by-step explanation:

To factor an equation, break the polynomial into two binomials which multiply to make it. Find two numbers that multiply to C and add to B from $ax^2 + bx + c$.

-1 and 5 multiply to -5 and add to 4.

$x^2+4x-5 = (x+5)(x-1)$

The zeros are the factors set equal to 0 and solved.

(x+5) = 0

x=-5

(x-1) = 0

x=1