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Xelga [282]
3 years ago
14

5/x+1 ÷ 6/3x+3 divide

Mathematics
1 answer:
Shalnov [3]3 years ago
7 0
Here is how to work that problem out. (check the picture)

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A sequence is formed by adding 1 to each square number.
MrRa [10]

Answer:

32 nd term

Step-by-step explanation:

The formula for the sequence is

n² + 1 ( that is 1 added to each square number )

Equate to 1025 and solve for n

n² + 1 = 1025 ( subtract 1 from each side )

n² = 1024 ( take the square root of both sides )

n = \sqrt{1024} = 32

6 0
3 years ago
In an endurance race, Rachel ran
Reil [10]

Answer:

31\frac{1}{5}\ miles

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

so

The distance is equal to multiply the speed by the time

we have

speed=9\frac{3}{5}\ \frac{miles}{hour}

time=3\frac{1}{4}\ hours

distance=(9\frac{3}{5})(3\frac{1}{4})

Convert mixed number to an improper fraction

9\frac{3}{5}=9+\frac{3}{5}=\frac{9*5+3}{5}=\frac{48}{5}

3\frac{1}{4}=3+\frac{1}{4}=\frac{3*4+1}{4}=\frac{13}{4}

substitute

distance=(\frac{48}{5})(\frac{13}{4})=\frac{624}{20}=31,2\ miles

Convert to mixed number

31.2\ mi=31+0.2=31+\frac{1}{5}=31\frac{1}{5}\ miles

3 0
3 years ago
What is the -2 squared -2
oksano4ka [1.4K]

Answer: the answer is negative one over four

-1/4






6 0
4 years ago
While traveling in Canada, a police officer pulls you over for speeding. The posted speed limit is 100
torisob [31]

Answer:

Speeding at 160.934 km/hr

Step-by-step explanation:

1 mile = 1.609344 kilometers

1.609344 * 100 = 160.934 kilometers

8 0
3 years ago
Read 2 more answers
What is th resulting true inequality ​
lorasvet [3.4K]

Answer:

10>-15

Step-by-step explanation:

The given inequality is:

-2<3

The inequality has to be multiplied by -5.

The multiplication is same as multiplying a normal equation with a number. The only difference is that the sign of inequality is changed when it is multiplied with a negative number.

So,

-2(-5) < 3(-5)

10>-15

So the correct answer is the last option ..

8 0
3 years ago
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