Answer: D
Step-by-step explanation:
I substituted in the value of x (2) to see if it gave me the value of y (1) because that’s the point it gave on g(x).
The only equation that worked was D.
1/2*2=1 then 1^2=1
Answer:
58.3% to the nearest tenth.
Step-by-step explanation:
The prime numbers from 1 to 6 are 2,3 and 5.
The probability of a prime number taken from the result of the 300 throws:
= (sum of the frequencies for 2, 3 and 5) / ( total throws)
= (60 + 55 + 60) / 300
= 0.5833 or 58.3%.
Let the integers be x and x + 2, then
x + x + 2 = 3(x + 2) - 2x
2x + 2 = 3x + 6 - 2x
2x + 2 = x + 6
2x - x = 6 - 2
x = 4
Therefore, the integers are 4 and 6
The rational root (or zero) theorem says a polynomial's rational zeros must have factors of the constant in the numerator and those of the leading coefficient in the denominator.
Here the leading coefficient is 1 and the constant is 5, so our only possibilities for rational roots are 1, -1, 5, -5
We try them each in term
1-3+1+5=6 nope
-1 -3 -1 +5 = 0 yes, x = -1 is a rational zero
5 and -5 don't work either so we're left with
Final answer: x = -1
Let's call the three numbers a, b, and c.
Now we can turn the information we are given into equations.
The sum of the three numbers is 26:
a + b + c = 26
Twice the first (2 times a) minus the second (2 times a minus b) is 2 less than the third:
2a - b = c - 2
The third is the second minus three times the first:
c = b - 3a
Counting what we have here, we now have three equations and three variables: enough to solve the whole system of equations.
The third equation gives us c directly, so we can start there and substitute into the second equation:
2a - b = (b - 3a) - 2
2a + 3a = b + b - 2
5a = 2b - 2
Let's get one of these variables on its own so we can continue with the substitution:
5a + 2 = 2b
b = (5a + 2) / 2
Now we have c in terms of a and b, and b in terms of just a. So let's use the first equation and substitute to find out what a is:
a + b + c = 26
a + (5a + 2) / 2 + (b - 3a) = 26
a + (5/2)a + 1 + (5a + 2) / 2 - 3a = 26
7/2a + 1 + 5/2a + 1 - 3a = 26
12/2a + 2 - 3a = 26
6a - 3a = 26 - 2
3a = 24
a = 8
At last, we have solved for one of the variables. Now, plug this into the equation for b to find b:
b = (5a + 2) / 2 = (5(8) + 2) / 2 = (40 + 2) / 2 = 42 / 2 = 21
Now we have a and b. Time to find c!
a + b + c = 26
(8) + (21) + c = 26
29 + c = 26
c = 26 - 29
c = -3
<span>So our values for a, b, and c are 8, 21, and -3.</span>
