A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Hello :
the line parallel to the x-axis if : ( a = 0 and b <span>≠ 0)
for exemple : a = 0 and b= 3 the line has the equation ; y = 2</span>
The answer is the 3 option
Hello there!
Answer:
You can also round up to the nearest tenths is 15.1 to 15.0 and its going to be stay.
Step-by-step explanation:
First you had to switch sides of equation form.
Then you add by 0.3 from both sides of equation form.
And finally, simplify by equation. You can also cross out by -0.3+0.3 and it gave us equal to zero. Then you add 14.8+0.3 and it equal to 15.1. You had to used their variable and its should be the right answer.
Hope this helps!
And thank you for posting your question at here on brainly, and have a great day.
-Charlie
<span> SO in total, Emily and Sarah had a total of 80
dollars in which Emily had twice as much as Sarah.
Let’s solve to find out how much their Money is.
=> Since the ratio of the given data is 2:1, 2 + 1 =3, so let’s divide 80 by
3
=> 80 / 3 = 26.667 ,
=> Emily has twice as this.
=> 26.667 * 2 = 53.33
=> Sarah has 26.67
Now, Sarah spent 1/3 of her money
=> 26.67 / 3 = 8.89 – her remaining money
Emily spent 17 dollars of her money
=> 53.33 – 17 = 36.33</span>
