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3 years ago

Ok so I need help on this ,asap plz :)

Mathematics

1 answer:

crimeas [40]3 years ago

3 0

40=6.32
75=8.66
90=9.49
245=15.65
450=21.21
640=25.30
675=25.98

Hope this helped you

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Answer:

I believe it is 2 grams.

Step-by-step explanation:

there are 1000 grams in 1 kg, there are 500 crayons, therefore each crayon weighs 2 grams

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3 years ago

You and your four friends are going to a concert. The total price for the tickets was $118.75 which includes a $10 service fee.

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3 years ago

Write an expression for the eighth partial sum of the series using summation notation

balandron [24]

Answer:

option B

Step-by-step explanation:

9/10 + 6/5 + 3/2...........

We find the difference between the terms

$\frac{6}{5} - \frac{9}{10}$

$\frac{12}{10} - \frac{9}{10} = \frac{3}{10}$

We will get the same difference when we subtract consecutive terms.

so , d= 3/10, a= 9/10

we find the formula for nth term

a_n = a+(n-1) d

$a_n = \frac{9}{10} + (n-1)\frac{3}{10}$

$a_n = \frac{9}{10} +\frac{3}{10}n-\frac{3}{10}$

$a_n = \frac{6}{10} +\frac{3}{10}n$

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we need to find eighth partial sum so we take n=1 to 8

sum of 8 terms ( $\frac{3}{5} +\frac{3}{10}n$ )

So option B is correct

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3 years ago

Given that f(x) = x + 3<br> a) Find f(2)

Nataly_w [17]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

In the above question, it is given that :

$\qquad \sf \boxed{ \sf f(x) = \frac{x + 3}{2} }$

A.) Find f(2) :

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{2 + 3}{2}$

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{5}{2}$

$\qquad \sf \dashrightarrow \: f(2) = 0.5$

B.) Find ${ \sf {f}^{-1}(x) }$ :

$\qquad \sf \dashrightarrow \: let \: y = f (x)$

so, we can write it as :

$\qquad \sf \dashrightarrow \: y = \dfrac{x + 3}{2}$

$\qquad \sf \dashrightarrow \: 2y = x + 3$

$\qquad \sf \dashrightarrow \: x = 2y - 3$

Now, put x = ${ \sf {f}^{-1}(x) }$ , and y = x and we will get our required inverse function ~

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3$

C.) Find ${ \sf {f}^{-1}(12) }$ :

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 36- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 33$

7 0

10 months ago