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3 years ago

Find a. Round to the nearest tenth:

Mathematics

1 answer:

Ulleksa [173]3 years ago

6 0

Step-by-step explanation:

In the following triangle, a= ? , b= 2cm.

m<B= 105° , m<C = 15° ,m< A =?

Now, we know that sum of the interior angles of the triangle = 180°

m<B+m<C +m< A =180°

105°+15°+m< A=180°

m< A= 180- 120° = 60°

$\frac{ \sin( A) }{a} = \frac{ \sin(B) }{b}$

$\frac{ \sin(60) }{a} = \frac{ \sin(105) }{2}$

$a = \frac{ \sin(60) }{ \sin(105) } \times 2$

$a = 1.79$

$a = 1.8$

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Why is (-3,6] a better answer than (-3,6)

Pani-rosa [81]

(-3, 6) includes all numbers between -3 and 6 but it does not include -3 and 6.

when you put square parentheses you include the number on the edge

so if an anwser includes all numbers between -3 and 6 and the number 6 it's correct to write (-3,6]

7 0

1 year ago

The following question has two parts. First, answer part A. Then, answer part B.

Pie

Answer:

When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.

If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.

Beyond zero, though, no integer has factors whose magnitudes are greater than its own. And that's a principle that can be extended even to the complex integers

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

When an object is thrown upwards with a speed of 64 ft/sec, its height above the ground is given by the function h(t)=−16t2+64t

Svet_ta [14]

Answer:

The object will reach its highest point 0.5 seconds after it has been thrown.

Step-by-step explanation:

The object reaches its maximum height when velocity is equal to zero, the velocity is the derivative of function height. That is:

$v(t) = \frac{d}{dt}h(t)$ (1)

Where $v(t)$ is the velocity of the object at time $t$ , in feet per seconds.

If we know that $h(t) =-16\cdot t^{2}+64\cdot t$ and $v(t) = 0\,\frac{ft}{s}$ , then the time when object reaches its highest point is:

$v(t) = -32\cdot t+64$

$-32\cdot t + 64 = 0$

$t = 0.5\,s$

The object will reach its highest point 0.5 seconds after it has been thrown.

3 0

2 years ago

Ahh help plss!! thank u

AnnZ [28]

Basically you’re multiplying them both
(x^3 + 2x - 1)(x^4 - x^3 + 3)

so you need to make sure you multiply each one, if you do it right, you should end up with
x^7 - x^6 + 3x^3 + 2x^5 - 2x^4 + 6x -x^4 +x^3 -3

simplify by adding like terms
x^7 - x^6 + 2x^5 - 3x^4 + 4x^3 + 6x - 3

your answer would be the third option

4 0

2 years ago

Score Frequency

RUDIKE [14]

Scores on an AP Exam at a local high school are recorded in the table. What was the average score?

Answer: D) 4.266 is correct

Explanation:

We are given the below frequency table:

Score Frequency

1 | 0

2 | 3

3 | 4