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DedPeter [7]
4 years ago
14

I need help on how to write these functions and evalute the functions for each independent and dependent value. thank you

Mathematics
1 answer:
morpeh [17]4 years ago
6 0

Take a clearer photo

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Write an equation in point-slope form for the line with a slope of -9 that passes through (-1,-3)
Elena L [17]

Answer:

y+3=-9(x+1)

Step-by-step explanation:

The formula for point slope is: y-y1=m(x-x1)

When:

m = slope

(x1,y1) = the point on the graph

-9 is the slope, so it replaces m. x1 is -1, and y1 is -3.

Plug in the values:

y-(-3)=-9(x-(-1)) OR y+3=-9(x+1)

6 0
3 years ago
Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s
stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

where t_{0.025} is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
3 years ago
PLEASE HELP!! URGENT!!
ArbitrLikvidat [17]
I believe it is 30


Explained
6 0
3 years ago
What is the total compound interest of a loan for $5,000 with an annual interest rate of 8 percent at the end of a two-year peri
jeka57 [31]
It's D because 5x8 = 40 and look at the extra zeros
5 0
4 years ago
Read 2 more answers
The moon is about 382,500km away from Earth. This distance actually varies by about 22,500km. What are the maximum and minimum d
KiRa [710]

Answer:

The minimum distance to the moon is of 360,000 km and the maximum distance is of 405,000 km

Step-by-step explanation:

The maximum distance is found adding the variation.

The minimum distance is found subtracting the variation.

We have that:

Distance: 382,500 km

Variation: 22,500 km

So

Maximum distance: 382500 + 22500 = 405,000 km

Minimum distance: 382500 - 22500 = 360,000 km

The minimum distance to the moon is of 360,000 km and the maximum distance is of 405,000 km

6 0
3 years ago
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