You think I know right? yeah so no way boy I'm so sorry not my intencion
Answer:
(-1,8)
(4,-27)
Step-by-step explanation:
y+7x=1
Let x = -1 and find y
y+7(-1)=1
y -7 =1
Add 7 to each side
y-7+7 = 1+7
y = 8
(-1,8)
Let x = 4 and find y
y+7(4)=1
y +28 =1
Subtract 28 from each side
y+28-28 = 1-28
y = -27
(4,-27)
Answer:
Least positive integer divisible by the numbers 2, 4, and 7 is 28
Step-by-step explanation:
We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM
First lets List all prime factors for each number.
Prime Factorization of 2
2 is prime => 
Prime Factorization of 4 is:
2 x 2 => 
Prime Factorization of 7 is:
7 is prime => 
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 7 = 28
Answer:
c = 15 ft
Step-by-step explanation:
a^2 + b^2 = c^2
9^2 + 12^2 = c^2
c^2 = 225
c = √225
<u>c = 15 ft</u>