Please help!!! asap!!!

Mathematics

1 answer:

quester [9]1 year ago

5 0

Answer:

x = 11 cos 22 = 11 * .927 = 10.2

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Write the percent shown by each model. Explain your reasoning.

Sphinxa [80]

A) 1/3=33 1/3%
B) 2/3=66 2/3%
C) 1/6=16 2/3%

A) YOU CAN TURN THE FRACTION 1/3 INTO A DECIMAL WHICH WILL BE AROUND 0.333. THEN YOU TURN THE DECIMAL INTO A PERCENT. YOU CAN MOVE THE DECIMAL TWO PLACES TO THE RIGHT. THAT GIVES YOU 33.3% OR 33 1/3% THIS ALSO APPLIES TO B BUT WITH 0.666 AND 66.6%

FOR C, YOU DO THE SAME. 1/6 AS A DECIMAL IS 1.666. YOU MOVE THE DECIMAL TWO PLACES TO THE RIGHT. 16.6% OR 16 2/3%

HOPE THIS HELPED.

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3 years ago

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Verizon [17]

5*5+5=30 5*5-15=10 30/10= 3

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2 years ago

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BRAINLIEST! URGENT! Please help me, If you can explain how you got the answer and if you answer both questions, I will mark you

anastassius [24]

Answer:

1. I have simplified the first question:

$x=\frac{10-ab}{a-4};\quad \:a\ne \:4$

2. I have found the parabola properties:

$\left(h,\:k\right)=\left(\frac{5}{2},\:\frac{25}{4}\right),\:p=-\frac{1}{4}$

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2 years ago

Determine whether the set of vectors <img src="https://tex.z-dn.net/?f=%20v_%7B1%3D%283%2C2%2C1%29%2C%20v_%7B2%7D%20%3D%28-1%2C-

Korolek [52]

Since each vector is a member of $\mathbb R^3$ , the vectors will span $\mathbb R^3$ if they form a basis for $\mathbb R^3$ , which requires that they be linearly independent of one another.

To show this, you have to establish that the only linear combination of the three vectors $c_1\mathbf v_1+c_2\mathbf v_2+c_3\mathbf v_3$ that gives the zero vector $\mathbf0$ occurs for scalars $c_1=c_2=c_3=0$ .

$c_1\begin{bmatrix}3\\2\\1\end{bmatrix}+c_2\begin{bmatrix}-1\\-2\\-4\end{bmatrix}+c_3\begin{bmatrix}1\\1\\-1\end{bmatrix}=(0,0,0)\iff\begin{bmatrix}3&-1&1\\2&-2&1\\1&-4&-1\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix}=\begin{bmatrix}0\\0\\0\end{bmatrix}$

Solving this, you'll find that $c_1=c_2=c_3=0$ , so the vectors are indeed linearly independent, thus forming a basis for $\mathbb R^3$ and therefore they must span $\mathbb R^3$ .

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2 years ago

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JulsSmile [24]

$C=8\pi fb\\
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2 years ago