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elena55 [62]
2 years ago
13

Please help!!! asap!!!

Mathematics
1 answer:
quester [9]2 years ago
5 0

Answer:

x = 11 cos 22 = 11 * .927 = 10.2

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General admission to the fair is $8.00, and rides cost $3.00 each.
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What is the equation?
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Solve (X + 6)(x - 4) = -16<br> O {-4, 6)<br> O {-4, 2]<br> O (-12, 22)
masya89 [10]

Answer:

x=2 or x=−4

Step-by-step explanation:

Let's solve your equation step-by-step.

(x+6)(x−4)=−16

Step 1: Simplify both sides of the equation.

x2+2x−24=−16

Step 2: Subtract -16 from both sides.

x2+2x−24−(−16)=−16−(−16)

x2+2x−8=0

Step 3: Factor left side of equation.

(x−2)(x+4)=0

Step 4: Set factors equal to 0.

x−2=0 or x+4=0

x=2 or x=−4

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3 years ago
What is root3(root3 - 1)
Alenkasestr [34]

Answer:

  • 3 - root3 or 3 - √3

Step-by-step explanation:

  • root3(root3 - 1) =
  • √3(√3 - 1) =
  • √3(√3) - √3(1) =
  • √3² - √3 =
  • 3 - √3
  • 3 - root3
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(Urgent) Worth 10 points 7.3
Novosadov [1.4K]

Step-by-step explanation:

A straight line adds up to 180°

m+3m=180°

4m=180°

m=45°

3m=45°

angle CBD=3(45)

=135°

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add the term that makes the given expression into a perfect square. write the result as the square of a bracketed expression c s
Molodets [167]
<h2>Perfect Squares</h2>

Perfect square formula/rules:

  • a^2+2ab+b^2=(a+b)^2
  • a^2-2ab+b^2=(a-b)^2

Trinomials are often organized like ax^2+bx+c.

The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.

  • Perfect square trinomial: ax^2+bx+(\dfrac{b}{2})^2
  • or ax^2-bx+(\dfrac{b}{2})^2

<h2>Solving the Question</h2>

We're given:

  • c^2-4c

In a trinomial, we're given the ax^2 and bx values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:

  • 4 ÷ 2 = 2
  • 2² = 4

Therefore, the term that we can add is + 4.

c^2-4c+4

To write this as the square of a bracketed expression, we can follow the rule a^2-2ab+b^2=(a-b)^2:

(c-2)^2

<h2>Answer</h2>

c^2-4c+4

(c-2)^2

4 0
2 years ago
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