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Hunter-Best [27]
3 years ago
7

In which place is the first digit of the quotient 3589÷80

Mathematics
1 answer:
givi [52]3 years ago
8 0
First you actually find the quotient so divide


3589/80

Which is = 44.86

First digit is 4 when you look at the quotient, starting from the left
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64 + 5 = 69
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What is the (10) for?
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2(10) is implied multiplication

Step-by-step explanation:

( 18+2) + 2(10) ÷4 -2

PEMDAS

Parentheses first

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Then exponents ( we have none)

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25 -2

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2(10) is implied multiplication

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There are 750 people at a football game. Out of this number, 320 are students. What percent of the people at the football game a
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Answer:

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Step-by-step explanation:

i dont lnow

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3 years ago
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BartSMP [9]

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Step-by-step explanation:

4 0
3 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
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