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Fed [463]
3 years ago
9

Change one letter in the word cave to solve it: A curved stick_______

Mathematics
1 answer:
scZoUnD [109]3 years ago
6 0
Cane, came .....................................
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Anyone ...Pls solve
expeople1 [14]
Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.

Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs

Solve for n
4n/9-n(1/5+1/4) = -3 
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540

Total number of products bought
= n+n = 540+540 = 1080
6 0
3 years ago
If invisible braces cost $500 more than metal braces. Metal braces cost $4,800. How much do invisible braces cost?
Gnesinka [82]
Invisible braces would cost 5300. I think that’s it. Hope that helped
4 0
3 years ago
Read 2 more answers
If you become a. . what Will you do
Gnoma [55]

Answer:

if you becomes a.. what is this mean

8 0
3 years ago
Read 2 more answers
How do you find the mode median the mean to range in stem and leaf plots
Julli [10]
The median is the middle line. Range is the the lowest value subtracted from the highest value. Mode is the most often occurring number. The mean is the average of all the data.
6 0
3 years ago
If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun
AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

               Nonsmokers      Light Smoker     Heavy smoker      Total

Men                        303                     35                           37        375

Women                   413                     31                            45        489

Total                        716                     66                           82        864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

82C2=\frac{82!}{2!(82-2)!}=3321

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

864C2=\frac{864!}{2!(864-2)!}=372816

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908

4 0
3 years ago
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