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ASHA 777 [7]
4 years ago
12

When a file has been opened using the 'r' mode specifier, which method will return the file's contents as a string??

Computers and Technology
1 answer:
topjm [15]4 years ago
5 0
Assuming we're talking C here:

I would opt for fread() with the following notes:
- there are no guarantees that the whole file counts as one string.
- you need to know the length of the file to allocate enough memory.
- you need to append a trailing 0 in memory to terminate the string.

fgets() does return a 0-terminated string but is not exactly what is asked since it only reads until the next newline character which may be in the middle of the file.
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Write a zip code class that encodes and decodes 5-digit bar codes used by the U.S. Postal Service on envelopes. The class should
8_murik_8 [283]

Answer:

#include<iostream>

#include<string>

using namespace std;

class zip_code

{

private:

int zipcode;

string get_string(int num)

{

string str="";

if(num == 0) return "11000";

if(num>7)

{

str.append("1");

num = num-7;

}

else

str.append("0");

if(num>4)

{

str.append("1");

num = num-4;

}

else

str.append("0");

if(num>2)

{

str.append("1");

num = num-2;

}

else

str.append("0");

if(num>1)

{

str.append("1");

num = num-1;

}

else

str.append("0");

str.append("0");

return str;

}

public:

zip_code(int barcode)

{

if(barcode<10000 || barcode>99999)

cout <<"Invalid Bar code passed to constructor." << endl;

else

zipcode = barcode;

}

zip_code(string barcode)

{

if(barcode.length()>27)

cout <<"Invalid Bar code passed to constructor." << endl;

else

{

int zipper = 0;

string str_local = barcode.substr(1,barcode.length()-2);

for(int i=0; i<str_local.length()-5; i+=5)

{

int local = 0;

local = 7*(str_local[i]-'0') +

       4*(str_local[i+1]-'0') +

       2*(str_local[i+2]-'0') +

       1*(str_local[i+3]-'0');

if(local == 11) local = 0;

       zipper = zipper*10 + local;

}

zipcode = zipper;

}

}

string getZipcode()

{

string str = "1";

int first = zipcode/10000;

int second = (zipcode - first*10000)/1000;

int third = (zipcode - first*10000-second*1000)/100;

int fourth = (zipcode - first*10000-second*1000-third*100)/10;

int fifith = (zipcode - first*10000-second*1000-third*100-fourth*10);

str.append(get_string(first));

str.append(get_string(second));

str.append(get_string(third));

str.append(get_string(fourth));

str.append(get_string(fifith));

str.append("1");

return str;

}

int get_zipCode()

{

return zipcode;

}

};

int main()

{

zip_code z1(123456);

zip_code z2(99504);

cout << z2.getZipcode() << endl;

system("pause");

return 0;

}

4 0
4 years ago
What is parallelism of microinstruction
Kitty [74]
The answer is Hardware level works upon dynamic parallelism whereas, the software level works on static parallelism. Dynamic parallelism means the processor decides at run time which instructions to execute in parallel,
8 0
3 years ago
How does Technology impact any profession or occupation?
Brrunno [24]

Technology can create or dimish occupations.

Technology can also make the job easier

8 0
3 years ago
Create an ArrayList of strings to store the names of celebrities and athletes. Add 5 names to the list. Process the list with a
mr Goodwill [35]

Answer:

// ArrayList class is imported

import java.util.ArrayList;

// Iterator class is imported

import java.util.Iterator;

// Main class is defined

class Main {

   // main method to begin program execution

   public static void main(String args[]) {

       // names ArrayList of String is defined

       ArrayList<String> names = new ArrayList<>();

       // 5 names are added to the list

       names.add("John");

       names.add("Jonny");

       names.add("James");

       names.add("Joe");

       names.add("Jolly");

       // for loop to print the names inside the arraylist

       for(int index = 0; index <names.size(); index++){

         System.out.println(names.get(index));

       }

       

       // A blank line is printed

       System.out.println();

       // A newMethod is called with names as argument

       newMethod(names);

       // A blank line is printed

       System.out.println();

       // Instance of Iterator class is created on names

       Iterator<String> iter

           = names.iterator();

 

       // Displaying the names after iterating

       // through the list

       while (iter.hasNext()) {

           System.out.println(iter.next());

       }

   }

   // the newmethod is created here

   public static void newMethod(ArrayList<String> inputArray){

     // A new name is added at index 2

     inputArray.add(2, "Smith");

     // the name in index 4 is removed

     inputArray.remove(4);

     // for each is used to loop the list and print

     for (String name : inputArray) {

       System.out.println(name);

       }

   }

}

Explanation:

The code is well commented. An output image is attached.

7 0
4 years ago
what are some of the challenges that could arise from setting up a file management system on a computer
seropon [69]
A virus maybe or ransomware
7 0
3 years ago
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