Answer:B
Explanation: your co workers might not know English so you would need to learn their language :)
The Correct answer would be C. <span>microphone,mouse,scanner
microphone you talk into to give info (data)
a mouse you use to click on objects to give input
a scanner you input a paper/object
hope this helps!! :)
</span>
Answer:
(A) A web page will not display in a browser unless it passes syntax validation testing.
(C)A web page must pass syntax validation testing before it is used.
Explanation:
A website is a collection of related web pages. A web page is an electronically arranged content page, designed and developed using web development application and language tool and hosted on a web server.
Web page or application development follows a series of well defined stages called software development life cycle (SDLC). The web application must go through these processes from birth to the end-of-life of the application.
The validation testing in SDLC, consisting of unit, acceptance and loading testing, which checks for syntax error or bugs on the written codes, because bugs could slow the loading of the page or even the display and browser compatibility of elements in the code.
Answer:
A I think I might be wrong
// Variable to keep track of array size
int length = 0;
// Array itself
int array[] = {};
// while loop will take input in the array until a negative number is entered
while(input>=0){
stdin = new Scanner(System.in);
array[length] = stdin;
length +=1;
}
// int variable to terminate while loop
int i =0;
// keep track of index of output array
int y =0;
while(arr[i] != length){
// making output array
int output[]={}; bool flag;
// put the element in out put array considering if it the desired one
output[y] = array [i];
// Now check if it was the desired?
for(int z=1;z<=length;z++){
if(array[i+z]!=output[y]){
flag = true;
}
else
{
output[y]=0;
y+=1;
}
if(array[i+z+1]=output[y] && flag == true){
output[y] = array[i];
y+=1;
}
}
//output the array
for(int o=0;o<y;o++)
System.out.println(output[o];
