The money in the Felix's account will be $6798 when he is 21.
<u>Step-by-step explanation:</u>
It is given that,
- The amount deposited is $2000.
- The account earns 6% compound interest.
- It is compounded annually for 21 years.
<u>To find the money in Felix's account after 21 years :</u>
The formula used here is,
⇒ 
where A is the amount after 21 years.
- P is the initial amount deposited ⇒ P = 2000
- r is the rate ⇒ r = 0.06
- n is the number of times interest is compounded per year⇒ n = 1
- t is the time period ⇒ t = 21
⇒ 
⇒ 
⇒ 
⇒ 
Therefore, The money in the Felix's account will be $6798 when he is 21.
Step-by-step explanation:
= 5- 2 + 12 /4
= 5 -2 + 3
= 8- 2
= 6
(8,5) because (6,5) is distance 2 from (6,3). So (8,5) will distance 2 from (8,3)
If you mean, what is 4x = 97......
4x = 97 -Divide both sides by 4
4x / 4 = 97 / 4
x = 24.25
Hope this helps you! Have a happy Thanksgiving, here's a turkey!
Answer:
(i) A truth table shows how the truth or falsity of a compound statement depends on the truth or falsity of the simple statements from which it's constructed.
Since A ∧ B (the symbol ∧ means A and B) is true only when both A and B are true, its negation A NAND B is true as long as one of A or B is false.
Since A ∨ B (the symbol ∨ means A or B) is true when one of A or B is true, its negation A NOR B is only true when both A and B are false.
Below are the truth tables for NAND and NOR connectives.
(ii) To show that (A NAND B)∨(A NOR B) is equivalent to (A NAND B) we build the truth table.
Since the last column (A NAND B)∨(A NOR B) is equal to (A NAND B) it follows that the statements are equivalent.
(iii) To show that (A NAND B)∧(A NOR B) is equivalent to (A NOR B) we build the truth table.
Since the last column (A NAND B)∧(A NOR B) is equal to (A NOR B) it follows that the statements are equivalent.