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2 years ago

3.

Mathematics

1 answer:

Jobisdone [24]2 years ago

4 0

Answer:

B and D

Step-by-step explanation:

B because if you dont and it is a real cop you would get an even bigger fine. D because you never know.

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Please show proof of how u got it ;-; :(

yanalaym [24]

First, divide the the polygon into two quadrilateral.

Then find the area of both quadrilaterals

The area of the small rectangle = 4 x 3 = 12 square feet

The area of the bigger rectangle = (9 - 3) x 14 = 6 x 14 = 84 square feet

Add both areas:

12 + 84 = 96 square feet

8 0

3 years ago

Point A of rectangle ABCD is located at coordinates (3,7). If rectangle ABCD is translated down 7 and left 5, what are the new c

uranmaximum [27]

Answer:

The new co-ordinates are A¹ ( -2 , 0)

Step-by-step explanation:

Step(i):-

Point A of rectangle ABCD is located at coordinates (3,7).

Type of transformation change of co-ordinate point

Vertical translation up 'd' units (x, y)→ (x, y +d)

Vertical translation down 'd' units (x, y)→ (x, y -d)

Horizontal translation left 'C' units (x, y)→ (x - c , y)

Horizontal translation right 'C' units (x, y)→ (x + c , y)

Step(ii):-

Given rectangle ABCD is translated down 7 and left 5

Given Point A(3 ,7)

Vertical translation down '7' units t

The new co-ordinate A¹ ( 3 , 7-7)→ A¹( 3, 0) and Horizontal translation left ''5' units

Now the new co-ordinates are A¹ ( 3-5 , 7-7)

Final answer:-

The new co-ordinates are A¹ ( -2 , 0)

7 0

2 years ago

Determine whether the equation defines y as a function of x. x+y=9 and x^2+y^2=1 and x=y^2

Murrr4er [49]

Answer:

Function: $x+y=9$

Not Function: $x^2+y^2=1$ and $x=y^2$

Step-by-step explanation:

Given

$x+y=9$

$x^2+y^2=1$

$x=y^2$

Required

Determine if $y$ is a function of $x$

Solving x+y=9

$x+y=9$

Make y the subject of formula

$y = 9 - x$

Hence; y is a function of x

Solving $x^2+y^2=1$

$x^2+y^2=1$

Subtract x² from both sides

$y^2=1 - x^2$

Square root of both sides

$y =\± \sqrt{1 - x^2}$

This implies that

$y =\sqrt{1 - x^2}$ or $y =-\sqrt{1 - x^2}$

Because $y$ can be any of those two expressions, it is not a function.

Solving $x=y^2$

$x=y^2$

Reorder

$y^2 = x$

Take square roots

$y = \±\sqrt{x}$

This implies that

$y = \sqrt{x}$ or $y = -\sqrt{x}$

Because $y$ can be any of those two expressions, it is not a function.

4 0

3 years ago

What is the graph of the function f(x) = the quantity of x plus 2, all over x minus 3

Andrej [43]

Answer:

Step-by-step explanation:

The given function is $f(x)=\frac{x+2}{x-3}$ and we need to graph it.

In order to graph this function, we'll find below things:

Horizontal asymptote:

Since the degree of both numerator and denominator is same. Hence, the horizontal asymptote is the ratio of leading coefficient of numerator to the leading coefficient of denominator.

Horizontal asymptote is y = 1/1 = 1

Vertical asymptote:

Vertical asymptote occurs where the denominator is zero.

$x-3=0\\x=3$

x-intercepts:

For x-intercept, y = 0

$\frac{x+2}{x-3}=0\\\\x+2=0\\x=-2$

y-intercepts:

For y-intercept, x= 0

$y=\frac{0+2}{0-3}=0\\\\y=-\frac{2}{3}$

Using these, we can draw the graph of the rational expression.

5 0

3 years ago

Read 2 more answers

Define jurisdiction.

timama [110]

The definition of jurisdiction as given in the choices would be authority over something. You have jurisdiction if you are free to make decisions on the matter.

Courts that try cases are called courts of original jurisdiction - which are usually trial courts.

3 0

3 years ago