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Luba_88 [7]
2 years ago
13

Is it possible for a number to be a rational number that is not an integer but is a whole number? PLEASE EXPLAIN

Mathematics
1 answer:
qwelly [4]2 years ago
4 0
No.  A simple definition of "integer" is "whole number", that is, a number without a fractional part.

The rational number doesn't have to be a whole number, but if it is, then it's an integer.
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Part B
vodomira [7]

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<h3>What is foreshadowing?</h3>

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8 0
2 years ago
What is the completely factored form of f(x) = 6x3 – 13x2 – 4x + 15?
masya89 [10]

We have to determine the complete factored form of the given polynomial

f(x)=6x^3-13x^2-4x+15.

Let x= -1 in the given polynomial.

So, f(-1)= 6(-1)^3-13(-1)^2-4(-1)+15 = -6-13+4+15 = 0

So, by factor theorem

(x+1) is a factor of the given polynomial.

So, dividing the given polynomial by (x+1), we get quotient as 6x^2-19x+15.

So, 6x^3-13x^2-4x+15 = (x+1)6x^2-19x+15.

= (x+1)(6x^2-10x-9x+15)

=(x+1)[ 2x(3x-5)-3(3x-5)]

= (x+1)(2x-3)(3x-5) is the completely factored form of the given polynomial.

Option D is the correct answer.

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B, parallel lines run the same direction next to each other.
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6 girls would need to join for the ratio to be the same
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Answer:

A

Step-by-step explanation:

I got it right in Edginuity.

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