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3 years ago

Solve the equation if 0 degrees<=x<=360 degrees. tanx=sqrt 3

Mathematics

1 answer:

storchak [24]3 years ago

4 0

Answer:

Step-by-step explanation:

hello :

tanx = √3 0°≤x≤360°

x = 60°

x=240°

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He ran a total of 10.50 miles

Step-by-step explanation:

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3 years ago

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La puntuación media de un examen final fue de 72 y la desviación típica de 9. El 10%

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Answer:

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3 years ago

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andreev551 [17]

Answer:

For the first question, x = 12.

For the second question, x = -9

Step-by-step explanation:

In the first question, in △RSQ,

RZ/RS = 1/2 = RY/RQ (given)

∠ZRY = ∠ZRY (common)

∴ △RZY ~ △RSQ (2 sides prop., inc. ∠)

∵ △RZY ~ △RSQ

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(x+2) / (3x-8) = 1/2

2(x+2) = (3x-8)

2x + 4 = 3x - 8

3x - 2x = 12

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In the second question, in △SRT,

SC/SR = 1/2 = SB/ST (given)

∠CSB = ∠CSB (common)

∴ △SCB ~ △SRT (2 sides prop., inc. ∠)

∵ △SCB ~ △SRT

∴ SC/SR = SB/ST = CB/RT = 1/2

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Hope this helped!

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3 years ago

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Answer:

See below

Step-by-step explanation:

● (7x^3 - 2x^2 -12) + (-3x^3 - 8x^2 +10x)

● 7x^3 - 2x^2 - 12- 3x^3 - 8x^2 + 10x

Combine like terms

● 7x^3 - 3x^3 -2x^2 - 8x^2 -12 + 10x

● 4x^3 - 10x^3 +10x -12

4 0

4 years ago

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Use an equation to find the value of k so that the line passing through (−4,k) and (6,−7) has a slope of −1/5.

Virty [35]

Answer:

k = -5

Step-by-step explanation:

Hi there!

$m=\displaystyle \frac{y_2-y_1}{x_2-x_1}$ where the two points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given information:

$\displaystyle -\frac{1}{5}= \displaystyle \frac{-7-k}{6-(-4)} \\\\\displaystyle -\frac{1}{5}= \displaystyle \frac{-7-k}{6+4} \\\\\displaystyle -\frac{1}{5}= \displaystyle \frac{-7-k}{10} \\\\\displaystyle -\frac{2}{10}= \displaystyle- \frac{-7-k}{10} \\\\-2=-7-k\\k=-5$

I hope this helps!

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3 years ago

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