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Tems11 [23]
3 years ago
5

How to do this question plz ​

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:

Alan= £4.20, Connor= £2.50

Step-by-step explanation:

Please see the attached picture for full solution.

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A sector of a circle has a central angle to 10° and arc length 28 pi units what is the radius of the circle
Dennis_Churaev [7]

Answer:

Radius = 504units

Step-by-step explanation:

Angle = 10°

Length of arc = 28π units

L = ∅/360 × 2πr

28π = 10/360 × 2πr

28π = 1/36 × 2πr

2πr = 28π × 36

π cancelled off.......

2r = 28 × 36

r = (28 × 36)/2

r = 28 × 18

r = 504units

8 0
3 years ago
If CD I EF, what is the mZFCD?
Margaret [11]

there is no picture. Can you upload a picture?

5 0
4 years ago
Need Help me ASAP!!!!
pantera1 [17]

Answer:

First option y=3/5x

Step-by-step explanation:

Because if you look on the graph, at x=5, y=3

in the equation, plug in x=5, you cancel out denominator left with y=3

please hit the heart button :) good luck

5 0
3 years ago
I need help with these questions for Quadratic functions
STALIN [3.7K]

9514 1404 393

Explanation:

1. The general form of a quadratic in standard form* is ...

  f(x)=ax^2+bx+c

An example is ...

  f(x)=2x^2+3x-5

The constant c is the y-intercept, so is the easiest bit of information to obtain in this form.

__

2. The general form of a quadratic in vertex form can be written as ...

  f(x)=a(x-h)^2+k

An example is ...

  f(x)=2(x -3)^2 -5

The ordered pair (h, k) is the vertex of the parabola, so is easy to obtain in this form. Arguably, it may be easier to identify the line of symmetry, x=h, since that requires looking at only one constant, instead of two.

_____

* In the UK, "standard form" is vertex form.

7 0
3 years ago
A line passes through (3, -2) and (6,2). Write an equation for the line in point-slope form.
snow_lady [41]

Answer:

4x - 3y -18 = 0 or y = 4x/3 - 6

Step-by-step explanation:

We will have to find the slope of the line first

The formula for slope:

m =\frac{y_{2}- y_{1} }{x_{2} -x_{1} } \\m= \frac{-2-2}{3-6}\\ =\frac{-4}{-3}\\ =\frac{4}{3}

The standard form of equation of a line is:

y = mx + b

We know m,

So the equation will be:

y= \frac{4}{3}x+b

We have to find the value of b, for that we will put any one of the point in the equation

So, putting (6,2)

2 = 4/3 * 6 + b

2 = 8 +b

b = -6

Putting the value of m and b in the standard form of equation of line,

y = mx + b\\y = \frac{4}{3}x+(-6)\\y = \frac{4}{3} x - 6\\Multiplying\ both\ sides\ by\ 3\\3y = 4x - 18\\4x - 3y -18 = 0 ..

7 0
3 years ago
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