Writing out: 4 to the power of negative 3 multiplied by 3 to the power of 4 multiplied by 4 to the power of 2 whole over 3 to the power of 5 multiplied by 4 to the power of negative 2
(4^(-3) * 3^4 * 4*2) / (3^5 * 4^(-2))
= (4^(-3+2) * 3^4) * 3^(-5) * 4^2
= 4^(1) * 3^(-1)
= 4/3
b. 4 over 3
Short Answer A is the bad guy. <<<<
The line should read
The large square area = the 4 triangles + the inner square.
(a + b)^2 = c^2 + 4 ( 1/2 * ab)
(a + b)^2 = c^2 + 2 ab
Answer:
i think it c because it hits 2 and 6 and when you divide it you get 1/3
