Answer:
three times the original diameter
Explanation:
From the wire's resistance formula, we can calculate the relation between the diameter of the wire and its length:
![R=\rho\frac{l}{\pi \frac{d^2}{4}}\\d=\sqrt{\rho \frac{4 l}{\pi R}}\\](https://tex.z-dn.net/?f=R%3D%5Crho%5Cfrac%7Bl%7D%7B%5Cpi%20%5Cfrac%7Bd%5E2%7D%7B4%7D%7D%5C%5Cd%3D%5Csqrt%7B%5Crho%20%5Cfrac%7B4%20l%7D%7B%5Cpi%20R%7D%7D%5C%5C)
Here, d is the wire's diameter,
is the electrical resistivity of the material and R is the resistance of the wire. We have ![l'=9l](https://tex.z-dn.net/?f=l%27%3D9l)
![d'=\sqrt{\rho \frac{4 l'}{\pi R}}\\d'=\sqrt{\rho \frac{4 (9l)}{\pi R}}\\d'=3\sqrt{\rho \frac{4 l}{\pi R}}\\d'=3d](https://tex.z-dn.net/?f=d%27%3D%5Csqrt%7B%5Crho%20%5Cfrac%7B4%20l%27%7D%7B%5Cpi%20R%7D%7D%5C%5Cd%27%3D%5Csqrt%7B%5Crho%20%5Cfrac%7B4%20%289l%29%7D%7B%5Cpi%20R%7D%7D%5C%5Cd%27%3D3%5Csqrt%7B%5Crho%20%5Cfrac%7B4%20l%7D%7B%5Cpi%20R%7D%7D%5C%5Cd%27%3D3d)
D. it is thickest in the middle
The answer is going be desert.
paraan ito ng pagrerespeto