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3 years ago

7. Jennifer purchased a video game console plus an

Physics

2 answers:

Mekhanik [1.2K]3 years ago

8 0

Answer:

21 games.

Explanation:

Here:

700 - 280 = 420

420 divided by 20 = we get 21

Elodia [21]3 years ago

8 0

21,
700-280=420
420/20=21 :)

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A crate rests on the flatbed of a truck that is initially traveling at 15 m/s on a level road. The driver applies the brakes and

lina2011 [118]

Answer:0.3

Explanation:

Given

velocity of car=15 m/s

truck brought to halt in a distance of 38 m

We know

$v^2-u^2=2as$

Final velocity (v)=0

$0-(15)^2=2(a)(38)$

$a=\frac{-225}{76}$

$a=-2.96 m/s^2$ (deceleration)

Therefore minimum coefficient of friction \mu will be

$\mu \times g=a$

$\mu =\frac{a}{g}$

$\mu =\frac{2.96}{9.8}=0.302$

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4 years ago

A dense metal sphere is dropped from a 10-meter tower, and at the exact same time an identical metal sphere is thrown horizontal

givi [52]

Answer:

A. Both spheres land at the same time.

Explanation:

The horizontal motion doesn't affect the vertical motion. Since the two spheres have the same initial vertical velocity and same initial height, they land at the same time.

7 0

3 years ago

Read 2 more answers

The acceleration of a particle traveling along a straight line is

Vlada [557]

Answer:

V= 14.2m/s

Explanation:

We know that acceleration= dv/dt

So 16m/s²=dv/ dt = v dv/ds

So this wil be

Integral of 16m/s² ds [at 2,2]= integral of v dv at[ 0, v]

So 16[s (3/2)/3/2] at ( s,3) = v²/2

At s= 6m

So v² = 64/3( 6^1.5-3^1.5)

= 14.2m/s

4 0

3 years ago

A 10 kg wagon is accelerated by a constant force of 60 N from an initial velocity of 5.0 m/s to a final velocity of 11 m/s. What

Readme [11.4K]

The answer is 274774

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3 years ago

Suppose you have a cylinder filled with diatomic oxygen (O2) and it is running low. The cylinder is shown above, is made of stee

Rudiy27

Answer:

The number of O₂ molecules that are left in the cylinder is 1.70x10²⁴.

Explanation:

The number of oxygen molecules can be found using the Ideal Gas law:

$PV = nRT$

Where:

P: is the pressure = 100 psi

V: is the volume = 10 L

n: is the number of moles =?

T: is the temperature = 20 °C = 293 K

R: is the gas constant = 0.082 L*atm/(K*mol)

Hence, the number of moles is:

$n = \frac{PV}{RT} = \frac{100 psi*\frac{1 atm}{14.7 psi}*10 L}{0.082 L*atm/(K*mol)*293 K} = 2.83 moles$

Now, the number of molecules can be found with Avogadro's number:

$n_{m} = \frac{6.022 \cdot 10^{23}\: molecules}{1\: mol}*2.83 moles = 1.70 \cdot 10^{24} \: molecules$

Therefore, the number of O₂ molecules that are left in the cylinder is 1.70x10²⁴.

I hope it helps you!

3 0

3 years ago