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pshichka [43]
3 years ago
10

NEED HELP ASAP!!!

Mathematics
2 answers:
Liula [17]3 years ago
3 0
The answer is 84tt yd2
Klio2033 [76]3 years ago
3 0
You need 3 formulas for this problem.

area of rectangle = length × width
circumference =
2\pi \times r
area of circle =
\pi \times {r}^{2}

you use circumference to find length of rectangle so you can find the area of the rectangle and the add up th e area for the rectangle and both circles for surface area

2\pi \times 3 = 18.84
18.84 \times 14 = 263.76
\pi \times {3}^{2} = 28.26

sa = 263.76 + 2(28.26) = 320.28

320.28 ÷ 3.14 = 102tt yd^2
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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and
goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}

Solve for S(t):

\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}

e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}

The left side is the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}

Integrate both sides:

e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt

e^{t/800}S(t)=64e^{t/800}+C

S(t)=64+Ce^{-t/800}

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

0=64+C\impleis C=-64

and so (b) the amount of sugar in the tank at time t is

S(t)=64\left(1-e^{-t/800}\right)

As t\to\infty, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

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iren2701 [21]

Answer:

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