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slega [8]
3 years ago
5

HELPPPPPPP MEEEEEEEEE

Mathematics
2 answers:
Rashid [163]3 years ago
7 0

Answer:

the 2nd table

Step-by-step explanation:

boyakko [2]3 years ago
3 0

Answer:

The first table

Step-by-step explanation:

<em>the third and fourth table are incorrect because it says Jo bought </em><em>25 apples </em><em>in total but in the third and fourth table there are </em><em>35 apples </em><em>in total.</em>

<em>the second table is incorrect because it said </em><u><em>three of the 12 large apples were red. </em></u><em>In the second table its says 12 large apples when its supposed to say three and the total in 15 instead of 12.</em>

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Help I am very bad at math I need answers by tomorrow if you can help please do​
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

3 0
3 years ago
What is 35% of 60? just had to be 20 words
Vladimir [108]

Answer:

35% of 60 = 21

4 0
2 years ago
Read 2 more answers
How do you classify a triangle by its sides
erik [133]
Triangle classification by sides would be scalene, no congruent sides; isosceles, at least 2 congruent sides; equilateral, 3 congruent sides.
6 0
3 years ago
Read 2 more answers
What would the correct answer be???
tiny-mole [99]

Answer:

8.27837797

I think this is correct im not completely sure.

8 0
3 years ago
Question 3, help please!
White raven [17]

The answer is not defined.

Explanation:

The given matrix is $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$

The matrix $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$ has dimensions 2\times 2

This means that the matrix has 2 rows and 2 columns.

Also, the matrix $\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$ has dimensions 2\times1

This means that the matrix has 2 rows and 1 column.

Since, the matrices can be added only if they have the same dimensions.

In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.

Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.

Hence, the addition of these two matrices is not defined.

4 0
3 years ago
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