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Sever21 [200]
3 years ago
11

One of the most common uses of spreadsheet programs are

Computers and Technology
2 answers:
Bas_tet [7]3 years ago
8 0
Common uses for spreadsheet documents be
-Organizing bills and money
-Groups of people and events
-Family plannings for weeks
-Grocery Lists.

I hope this helps!
Romashka [77]3 years ago
8 0

Answer:

 Spreadsheet:

The spreadsheet is one of the type of computer application which is used for storing the data in the tabular form. The spreadsheet is mainly developed for the paper accounting purpose in the computerized analog format system.

There are various types of common uses of the spreadsheet program are as follows:

  • In the spreadsheet, we can store the data and also sorting and editing the data at anytime according to the requirement.
  • We can also calculate and set our budget and also calculating taxes.  
  • We can also use the sheet for many business purpose for calculating productivity, revenue and performance of the company.

You might be interested in
The procedure call mystery(38) will yield which output? __________ a) 0 12 b) 12 0 c) 1 1 0 2 d) 1 1 1 1 e) 2 0 1 1 public void
Ivan

Answer:

Option b is the correct answer for the above question.

Explanation:

  • The mystery function is a recursive function that calls for the two times when the user passes 38 on the argument.
  • The first value is 38 and the second value is 2 for which that function is called.
  • When the value 38 is passed, then again 2 is passed because of the "mystery (n % 3);" statement.
  • This statement holds by the if condition which gives the true when the argument value is greater than 2.
  • Hence for the 2 value the if condition will not true and the function is not called again.
  • Then the 38/3 and 2/3 are printed whose value is 12 0, but it will print 0 12 because of the recursive function.
  • Hence option b is the correct answer while the other is not because other options does not states the output of this program.
3 0
3 years ago
HELP PLEASE!!!! Which type of prototyping is most often associated with the rapid prototyping development method?
Georgia [21]

Answer:

That will be Throwaway

6 0
3 years ago
What type of network access control uses Active Directory to scan a device to verify that it is in compliance?
Komok [63]

Answer:

Agentless NAC

Explanation:

An active directory is a kind of storage service that holds data of objects like user credentials, resource location etc, for permission and network access authentication.

Network access control is a form of computer network security that integrates security technology like antivirus, intrusion detection and prevention systems etc to system authorisation and authentication processes to control access to a network.

An agentless network access control uses the active directory to scan devices to confirm its compliance to security policies.

3 0
4 years ago
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
3 years ago
Array, destination contains the number of 10 cities numbered 1 to 10 that the products were shipped to. Hence, 10 quantities of
Naddik [55]

Answer:

#include <stdlib.h>

#include <stdio.h>

void func1(int product[]){

int orders[6]={0};

for(int i=0;i<70;i++){

orders[product[i]]++;

}

printf("Total number of each type of products that were bought\n");

for(int i=1;i<=5;i++){

printf("Product %d = %d\n",i,orders[i]);

}

}

void func2(int product[],int quantity[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

total_cost+= price[product[i]]* quantity[i];

}

printf("The total cost of all 70 orders = %.2f\n",total_cost);

}

void func3(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]==8){

total_cost+= price[product[i]]* quantity[i];

}

}

printf("The total cost of all products shipped to destination 8 = %.2f\n",total_cost);

}

void func4(int product[],int quantity[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders where each order is $50 or more = %d\n",total_orders);

}

void func5(int product[],int quantity[],int origination[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %d\n",total_orders);

}

void func6(int product[],int quantity[],int origination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]] * quantity[i]>=50){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %.2f\n",total_cost);

}

void func7(int origination[],int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_orders++;

}

}

printf("The total number of orders that originated from 3 and shipped to 8. = %d\n",total_orders);

}

void func8(int product[],int quantity[],int origination[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total cost of orders that originated from 3 and shipped to 8. = %.2f\n",total_cost);

}

void func9(int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_orders++;

}

}

printf("The total number of orders that was shipped to all destinations except to 8. = %d\n",total_orders);

}

void func10(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_cost += price[product[i]] * quantity[i];;

}

}

printf("The total cost of orders that was shipped to all destinations except to 8. = %.2f\n",total_cost);

}

int main(){

int product[70] = {4, 2, 4, 2, 4, 5, 5, 2, 2, 5, 5, 4, 3, 5, 4, 2, 5, 3, 1, 2, 2, 3, 3, 4, 5, 5, 4, 5, 3, 5, 5, 1, 4, 5, 1, 5, 3, 2, 4, 1, 2, 4, 5, 1, 5, 5, 5, 5, 5, 2, 5, 1, 4, 4, 4, 2, 3, 3, 3, 3, 4, 3, 5, 5, 3, 2, 3, 5, 3, 2};

int quantity[70] = {10, 9, 6, 4, 10, 4, 9, 6, 10, 7, 3, 4, 4, 9, 1, 8, 9, 1, 5, 8, 7, 2, 3, 4, 10, 5, 6, 2, 1, 7, 2, 8, 6, 9, 8, 8, 7, 7, 9, 10, 6, 7, 8, 2, 1, 7, 6, 3, 3, 1, 8, 4, 10, 7, 1, 10, 6, 9, 8, 2, 4, 6, 1, 8, 2, 6, 10, 2, 6, 2};

int origination[70] = {2, 7, 5, 5, 7, 2, 7, 2, 7, 7, 5, 2, 5, 5, 5, 2, 2, 7, 2, 7, 7, 2, 2, 2, 2, 5, 7, 5, 7, 7, 5, 5, 2, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 2, 7, 2, 7, 5, 2, 2, 2, 5, 7, 2, 5, 5, 5, 7, 7, 2, 5, 2, 7, 5, 2, 5, 7};

int destination[70] = {8, 7, 3, 10, 2, 6, 4, 5, 1, 3, 5, 9, 5, 8, 6, 4, 3, 7, 1, 2, 7, 2, 8, 2, 2, 1, 2, 6, 10, 2, 7, 7, 8, 6, 8, 8, 4, 8, 3, 10, 6, 9, 4, 9, 5, 1, 7, 3, 1, 7, 5, 5, 4, 9, 3, 10, 8, 1, 1, 1, 1, 8, 10, 3, 5, 2, 8, 7, 4, 10};

float price[6]={0,11.95,7.95,19.95,24.95,15.25};

func1(product);

func2(product,quantity,price);

func3(product,quantity,destination,price);

func4(product,quantity,price);

func5(product,quantity,origination,price);

func6(product,quantity,origination,price);

func7(origination,destination);

func8(product,quantity,origination,destination,price);

func9(destination);

func10(product,quantity,destination,price);

}

Explanation:

The program inputs order, products and cities products are shipped.

After a series of conditional requirements being met, will output the destination each product os going to and the number of products with its associated price.

3 0
4 years ago
Read 2 more answers
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