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Maurinko [17]
3 years ago
7

NAND is logically complete. Use only NAND gates to constructgate-level circuits that compute the

Computers and Technology
1 answer:
Drupady [299]3 years ago
3 0

Answer:

Hi, for this exercise we have two laws to bear in mind:

Morgan's laws

NOT(А).NOT(В) = NOT(A) + NOT (B)

NOT(A) + NOT (B) = NOT(А).NOT(В)

And the table of the Nand

INPUT OUTPUT

A B A NAND B

0 0         1

0 1         1

1 0         1

1 1         0

Let's start!

a.

Input            OUTPUT

A       A     A NAND A

1         1             0

0        0            1

b.

Input            OUTPUT

A       B     (A NAND B ) NAND (A NAND B )

0         0            0

0         1            0

1          0             0

1          1             1

C.

Input            OUTPUT

A       B     (A NAND A ) NAND (B NAND B )

0        0           0

0        1             1

1         0            1

1          1            1

Explanation:

In the first one, we only need one input in this case A and comparing with the truth table we have the not gate

In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.

In the third case we have that the OR is A + B and we know in base of the morgan's law that:

A + B = NOT(NOT(А).NOT(В))

So, we have to negate the two inputs and after make nand with the two inputs negated.

I hope it's help you.

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Program 7 - Circle You write ALL the code, then run it - Produce the correct output. Turn in code and screen print of successful
fgiga [73]

Answer:

Here is the Circle class:

public class Circle {   // class definition

private int radius;    // private data member of type int of class Circle named radius that stores the value of radius

public Circle(int r) {   // parameterized constructor of class Circle that takes radius as argument

 radius = r;  }    // sets value of radius as r

public int getRadius() {   // accessor method to get the value of radius

 return radius;  }   // returns the current value of radius

public int Diameter() {   // method to compute diameter of a circle

 return radius * 2;  }   // multiply radius value by 2 to compute diameter of Circle

 

public double Area() {   // method to compute area of a circle

 return Math.PI  * Math.pow(radius, 2);   }   //the formula of area is

π x radius² where value of π is get using Math.PI

 

 public double Circumference() {   // // method to compute circumference of a circle

 return 2* Math.PI * radius;   }   }  //the formula of circumference is

2 x π x radius where value of π is get using Math.PI

Explanation:

Here is the Main class:

import java.util.Scanner;  //to accept input from user

public class Main {  //definition of Main class

public static void main(String[] args) {  //start of main method

   

    Scanner scanner = new Scanner (System.in);  //creates Scanner object to take input from user

    System.out.println("Enter radius: ");  //prompts user to enter radius

    int r = scanner.nextInt();  //reads the value of radius from user

 Circle c = new Circle(r);  // calls Constructor of Circle passing r as argument to it using the object c of class Circle

 

    if(c.getRadius()<=0){  //calls getRadius method to get current value of radius using objec and checks if this value (input value of r ) is less than or equal to 0

        System.out.println("Error!");   }  //when above if condition evaluates to true then print this Error! message

    else {  //if the value of radius is greater than 0

System.out.println("the radius of this Circle is: " +c.getRadius());  //calls getRadius method to return current value of r (input value by user)

System.out.println("the diameter of this Circle  is: " + c.Diameter());  //calls Diameter method to compute the diameter of Circle and display the result on output screen

System.out.printf("the circumference of this Circle  is: %.2f", c.Circumference());  //calls Circumference method to compute the Circumference of Circle and display the result on output screen

System.out.println();  //prints a line

System.out.printf("the Area of this Circle  is: %.2f", c.Area()); } }  }

//calls Area method to compute the Area of Circle and display the result on output screen

The program and its output is attached.

7 0
3 years ago
Write code to take a String input from the user, then print the first and last letters of the string on one line. Sample run: En
Ainat [17]
<h2>Answer:</h2>

//import the Scanner class to allow for user input

import java.util.Scanner;

//Begin class definition

public class FirstAndLast{

   //Begin the main method

    public static void main(String []args){

       

       

       //****create an object of the Scanner class.

       //Call the object 'input' to receive user's input

       //from the console.

       Scanner input = new Scanner(System.in);

       

       //****create a prompt to tell the user what to do.

       System.out.println("Enter the string");

       

       //****receive the user's input

       //And store it in a String variable called 'str'

       String str =  input.next();

       

       //****get and print the first character.

       //substring(0, 1) - means get all the characters starting

       //from the lower bound (index 0) up to, but not including the upper

       //bound(index 1).

       //That technically means the first character.

       System.out.print(str.substring(0,1));

       

       //****get and print the last character

       //1. str.length() will return the number of character in the string 'str'.

       //This is also the length of the string

       //2. substring(str.length() - 1) - means get all the characters starting

       // from index that is one less than the length of the string to the last

       // index (since an upper bound is not specified).

       // This technically means the last character.

       System.out.print(str.substring(str.length()-1));

       

       

       

    }  // end of main method

   

} //end of class definition

<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.

The source code and a sample output have also been attached to this response.

To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
4c53f66d970acf88b251b2cf41bcdaf6.png
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Answer:

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You have just purchased a server with Windows Server 2016 Datacenter Edition installed. The server has 4 GB RAM, a 200 GB hard d
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Answer:

a. Install more RAM

Explanation:

According to my research on information technology, I can say that based on the information provided within the question this server will not work for you purpose unless you install more RAM. This is because Hyper-V server's have a minimum requirement of 4gb, therefore if you want to run 2 servers you can divide all the resources you have since they are enough but not the RAM since you only have the bare minimum for one server. You need to add atleast 4 gb more of RAM.

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