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MAXImum [283]
3 years ago
8

Use linear approximation, i.e. the tangent line, to approximate √16.4 as follows: Let f(x)=√x. Find the equation of the tangent

line
Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

L(x)=\frac{1}{8}x+2\\ L(16.4)=4.05

Step-by-step explanation:

The equation for a tangent line of f(x) in the point (a,f(a)) can be calculated as:

L(x) = f(a) + f'(a)(x-a)

Where L(x) is also call a linear approximation and f'(a) is the value of the derivative of f(x) in (a,f(a)).

So, the derivative of f(x) is:

f(x)=\sqrt{x} \\f'(x)=\frac{1}{2\sqrt{x} }

Then, to find the linear approximation we are going to use the point (16, f(16)). So a is 16 and f(a) and f'(a) are calculated as:

f(16)=\sqrt{16}=4\\f'(16)=\frac{1}{2\sqrt{16} }=\frac{1}{8}

Then, replacing the values, we get that the equation of the tangent line in (16,4) is:

L(x)=4+\frac{1}{8}(x-16)\\L(x) = \frac{1}{8}x+2

Finally, the approximation for \sqrt{16.4} is:

L(16.4)=\frac{1}{8}(16.4)+2\\ L(16.4)=4.05

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Step-by-step explanation:

<em><u>~Solve for y by simplifying both sides of the equation, then isolating the variable~</u></em>

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Step-by-step explanation:

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3 years ago
In triangle ABC segment DE is parallel to the side AC . (The endpoints of segment DE lie on the sides AB and BC respectively). F
Sophie [7]

Answer:

The length of DE is 14 cm.

Step-by-step explanation:

Given in triangle ABC segment DE is parallel to the side AC . (The endpoints of segment DE lie on the sides AB and BC respectively). we have to find the length of DE.

Given lengths are AC=20cm, AB=17cm, and BD=11.9cm

In ΔBDE and ΔBAC

∠BDE=∠BAC       (∵Corresponding angles)

∠BED=∠BCA       (∵Corresponding angles)

By AA similarity rule, ΔBDE~ΔBAC

∴their corresponding sides are in proportion

⇒ \frac{BE}{BC}=\frac{BD}{BA}=\frac{DE}{AC}

⇒ \frac{BD}{BA}=\frac{DE}{AC}

⇒ \frac{11.9}{17}=\frac{DE}{20}

⇒ DE=\frac{20\times 11.9}{17}=14cm

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3 years ago
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