Answer:
A = (5 x Z³) + (6 - X)
Step-by-step explanation:
given the information provided, this is the equation you're looking for
Answer:Find the distance between the parallel lines m and n whose equations are y = x + 4 and y = x - 6, respectively.
There are several ways to do this...here's one
Let (0, 4) be a point on the first line
Then.......a line with a negative reciprocal slope going through this point will have the equation :
y = -x + 4........so......we can find the intersection of this line with y = x - 6....set both equations equal
-x + 4 = x - 6 add x, 6 to both sides
10 = 2x divide both sides by 2
5 = x
So...using -x + 4, the y value at intersection = -1.......
So...we just need to find the distance from (0,4) to ( 5, -1) =
√[ (5)^2 + (4 + 1)^2 ] = 5√2 ≈ 7.07 units
Here's a pic....AB is the distance with A = (0,4) and B = (5, -1)
Step-by-step explanation:
A system of equations is:
B )
x + y = 375
x = 2 y - 60
We will solve this system:
2 y - 60 + y = 375
3 y = 435
y = 435 : 3
y = 145
x = 375 - 145
x = 230
Allan`s score was 230 and Dave`s score was 145.
Your answer is 4 1/2 your welcome
Ab+ac=a(b+c)
a is common factor
factor
6ab=2*3*a*b
9bc=3*3*b*c
common factor is 3*b or 3b
3b(2a)+3b(3c)=3b(2a+3c)
