Correct answer:
"All of these are equally affected."
When in Alzheimer's disease, all of the working memory is in peril. In early stages of Alzheimer's disease, all of these functions start to have problems. Phonological loop is basically the capacity to memorise speech or information in it. Central executive is the ability to switch attention from one activity to another that is needing more attention. The visuospatial sketch pad is the ability to handle visual and spatial information being able to judge distances for example. All of these are part o the working memory and are affected from the early stages of Alzheimer's disease.
Answer:
Number of bacteria required 
Explanation:
Given -
Size of each bacterium
micrometers long
These bacteria are arranged end to end.
The size of chain to be formed is equal to
centimetres
Let us say that in forming a chain of
centimetres nearly X number of individual bacterium are required.
hence, number of bacterium required to form
centimetres chain can be represented as

Number of bacteria required 
Violet and blue have the high frequencies (thus energy) of visible light. Red will be the least energy but lowest energy. And remember, chlorophyll is green because it reflects green into our eyes. Green is therefore not absorbed, so not used for photosynthesis.
Most bacterias are heterotrophs. Meaning they can't make their one good ( sadly :3)
Answer: 0.18
Explanation:
For the alleles, the percentage distribution of each is 'A' (90% = 0.9)
While 'a' (10% = 0.1)
Hence, 0.9 and 0.1 are the respective frequencies of each allele
Now, apply Hardy-Weinberg Equilibrium equation, where heterozygotes are represented by the 2pq term.
Therefore, the number of heterozygous individuals (Aa) is equal to 2pq which equals
2 × 0.9 × 0.1 = 0.18
Thus, the frequency of heterozygote is 0.18, while the percentage distribution in the population is 18%