4 years ago

1+tanA.tan2A = sec2A

Mathematics

1 answer:

yuradex [85]4 years ago

4 0

Answer:

Step-by-step explanation:

1+tan2A(tanA)=sec2A

Right hand side

sec2A=1cos2A=1cos2A−sin2A

=cos2A+sin2Acos2A−sin2A

=1+tan2A1−tan2A

=1−tan2A+2tan2A1−tan2A

=1−tan2A1−tan2A+2tan2A1−tan2A

=1+2tanA1−tan2A×tanA

=1+tan2A×tanA

=Left hand side

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