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alexdok [17]
3 years ago
11

Factor the following binomail: (2x^4 - 12x^7)

Mathematics
1 answer:
Ann [662]3 years ago
5 0
Hopes this helps:

Answer: 2x^4(1-6x^3)
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Which kind of decimals are irrational?
ella [17]

Answer:

D.) Those that never end and have no pattern

Definition:

An irrational number cannot be expressed as a ratio between two numbers and it cannot be written as a simple fraction because there is not a finite number of numbers when written as a decimal. Instead, the numbers in the decimal would go on forever, without repeating.

<em>Hope this helps : D</em>

6 0
3 years ago
Find the value for the variable expression p + 5 when p = 2.
sweet [91]
Replace all the variables with their values. In this case, we know the value of the variable p.

Now the expressions p + 5 becomes 2 + 5.

2 + 5 = 7

So, C. 7 is the answer.
7 0
4 years ago
Read 2 more answers
Write the standard form of the equation of each line. How do I find the slope and y-intercept with the graph for problem 6???
lisov135 [29]
The standard form for an equation is y=mx+b. You find the slope by using the formula of rise over run. This means that for problem 6 you first look to see if its positive or negative slope. The slope is positive if the line is going uphill and if its going downhill its negative. The slope would be negative for number 6 because it is going downhill. Then for the actualy slope you would start with rise. So you look at the point (0,1) and go up 3 until you hit the line of the other point and run over 2. So your slope would be -3/2.
5 0
3 years ago
(√x+1/√x)^2find dy/ dx and substitute 2 in dy/ dx
lions [1.4K]
Hello,
That's better.

I suppose y=( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )^2 \\&#10;&#10;y'=2*( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )*( \dfrac{1}{2 \sqrt{x} } - \dfrac{3}{2x \sqrt{x} } )

If x=2  then
y'=2*( \sqrt{2} + \dfrac{1}{ \sqrt{2} } )*( \dfrac{1}{2 \sqrt{2} } - \dfrac{3}{2*2* \sqrt{2} } )\\&#10;=2* \dfrac{2+ \sqrt{2} }{ \sqrt{2} } * \dfrac{1}{4*\sqrt{2} } *(-1)\\&#10;=- \dfrac{2+ \sqrt{2} }{4}

3 0
3 years ago
How to solve number 1?
Archy [21]
E(x)=5(x-1)(x+2)-(x+2)^2\\\\1)\ 5(x^2+2x-x-2)-(x^2+2x\cdot2+2^2)\\=5(x^2+x-2)-(x^2+4x+4)\\=5x^2+5x-10-x^2-4x-4\\=4x^2+x-14\neq4x^2+x+1\\\\2)\ E(x)=1\ for\ E(x)=4x^2+x+1\\\\4x^2+x+1=1\ \ \ \ |subtract\ 1\ from\ both\ sides\\4x^2+x=0\\x(4x+1)=0\iff x=0\ \vee\ 4x+1=0\\x=0\ \vee\ 4x=-1\\\boxed{x=0\ \vee\ x=-0.25}

3)\ H(x)=9x^2-(2x+1)^2\\\\a.\ H(x)=(3x)^2-(2x+1)^2=[3x-(2x+1)](3x+2x+1)\\=(3x-2x-1)(5x+1)=(5x+1)(x-1)\\\\b.\ H(x)=0\\\\(5x+1)(x-1)=0\iff5x+1=0\ \vee\ x-1=0\\5x=-1\ \vee\ x=1\\\boxed{x=-0.2\ \vee\ x=1}
5 0
3 years ago
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