Answer:
19.
log9(5x^2 + 10) - log9(10) = 1
<=> log9((5x^2 + 10)/10) = log9(9)
<=> (5x^2 + 10)/10 = 9
<=> 5x^2 + 10 = 90
<=> 5x^2 = 80
<=> x^2 = 16
<=> x = +/- (4)
20.
log5(2x^2 + 4) + log5(3) = 2
<=> log5((2x^2 + 4) x 3) = log3(9)
<=> 6x^2 + 12 = 9
<=> 6x^2 = -3
=> No real x satisfies. ( x^2 always larger or equal to 0)
21.
log6(8) + log6(7 - 2x^2) = 2
<=> log6(8 x (7 - 2x^2)) = log6(36)
<=> 56 - 16x^2 = 36
<=> 16x^2 = 20
<=> x^2 = 5/4
<=> x = +/- sqrt(5/4)
Hope this helps!
:)
Answer:

Step-by-step explanation:
The given expresion is

Recall that:

We apply this property to get:


We apply the quotient rule to get


The first choice us correct
Answer:

Step-by-step explanation:
Given
Let the angle be 

is co-terminal with -5
Required
Find 
Start by dividing 5 by 360 (ignore the negative)

The nearest integer greater than 0.0138 is 1.
<em>This implies that if you were to draw for this problem, the circle you would draw to show -5 degrees would go around 1 time</em>
So,
is calculated as:



Answer:
Area pf the regular pentagon is 193
to the nearest whole number
Step-by-step explanation:
In this question, we are tasked with calculating the area of a regular pentagon, given the apothem and the perimeter
Mathematically, the area of a regular pentagon given the apothem and the perimeter can be calculated using the formula below;
Area of regular pentagon = 1/2 × apothem × perimeter
From the question, we can identify that the value of the apothem is 7.3 inches, while the value of the perimeter is 53 inches
We plug these values into the equation above to get;
Area = 1/2 × 7.3× 53 = 386.9/2 = 193.45 which is 193
to the nearest whole number