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2 years ago

15

Given a quadratic function, y = ax2 + bx + c, what happens to the graph when "a" is positive? What happens to the graph when "a"

is negative?

1 answer:

Elanso [62]2 years ago

4 0

Answer:

when a is positive, the graph is a smiling graph. when a is negative the curve is a sad graph. thats how i remember it

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A city had population 67,255 on january 1, 2000, and its population has been increasing by 2935 people each year since then. A l

irina1246 [14]

We are given: On january 1, 2000 initial population = 67,255.

Number of people increase each year = 2935 people.

Therefore, 67,255 would be fix value and 2935 is the rate at which population increase.

Let us assume there would be t number of years after year 2000 and population P after t years is taken by function P(t).

So, we can setup an equation as

Total population after t years = Number of t years * rate of increase of population + fix given population.

In terms of function it can be written as

P(t) = t * 2935 + 67255.

Therefore, final function would be

P(t) = 2935t +67255.

So, the correct option is d.P(t) = 67255 + 2935t.

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(This photo didnt even get up yet!)

11Alexandr11 [23.1K]

Answer:

15 ways

Step-by-step explanation:

$\frac{6!}{4!(6-4)!}=\frac{6!}{4!2!}=15$

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What expression gives the volume of a sphere with radius 8

Natalija [7]

V=(4/3)(pi)(r^3)
V=(4/3)(pi)(8^3)
V=(4/3)(pi)(512)
V=(2048/3)(pi), or around 2144.660585

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A circle is described by the equation x2 + y2 + 14x + 2y + 14 = 0. What are the coordinates for the center of the circle and the

Alona [7]

We are given the expression of the equation of a circle that is x2 + y2 + 14x + 2y + 14 = 0. Using ocmpleting the squares:
x2 + y2 + 14x + 2y + 14 = 0(x+7)^2 + (y+1) ^2 = -14 + 49 + 1(x+7)^2 + (y+1) ^2 = 36 center thus is at (-7,-1) and the radius is equal ot square root of 36 equal to 6.

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the solutions to the inequality y > −3x 2 are shaded on the graph. which point is a solution? a). (0, 2) b). (2, 0) c). (1, −

PolarNik [594]

we have

$y> -3x+2$

The solution is the shaded area above the dotted line

we know that

If a point is a solution of the inequality, then the coordinates of the point must satisfy the inequality

We will verify all cases to determine the solution of the problem

<u>Case A)</u> Point $(0,2)$

$x=0\\y=2$

Substitute the value of x and y in the inequality and verify

$2> -3*0+2$

$2>2$ -------> is not true

therefore

the point $(0,2)$ is not a solution of the inequality

<u>Case B)</u> Point $(2,0)$

$x=2\\y=0$

Substitute the value of x and y in the inequality and verify

$0> -3*2+2$

$0>-4$ -------> is true

therefore

the point $(2,0)$ is a solution of the inequality

<u>Case C)</u> Point $(1,-2)$

$x=1\\y=-2$

Substitute the value of x and y in the inequality and verify

$-2> -3*1+2$

$-2>-1$ -------> is not true

therefore

the point $(1,-2)$ is not a solution of the inequality

<u>Case D)</u> Point $(-2,1)$

$x=-2\\y=1$

Substitute the value of x and y in the inequality and verify

$1> -3*(-2)+2$

$1>8$ -------> is not true

therefore

the point $(-2,1)$ is not a solution of the inequality

therefore

<u>the answer is the Point B</u>

$(2,0)$

To better understand the problem see the attached figure

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