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3 years ago

PLEASE HELP SUPER EASY 10 POINTS DUE TOMARROW

Mathematics

1 answer:

Volgvan3 years ago

5 0

It would be about 16.67 for a regular price of the Vans?

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Write a equation of a hyperbola given the foci and the asymptotes

professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

$\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}$

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}$

The asymptote of n hyperbola is expressed as

$y=\pm\frac{a}{b}(x-h)+k$

Given that the asymptotes are

$y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x$

This implies that

$a=3,\text{ and b=4}$

To evaluate the value of h and k,

$undefined$

3 0

1 year ago

PLEASE HELP

Ainat [17]

Answer: b

Step-by-step explanation:

8 0

2 years ago

Evaluate: (-4x+6) + (x-5)

Lady bird [3.3K]

Answer:

-3x+1

Step-by-step explanation:

8 0

3 years ago

Evaluate the expression when a = -3 and b=5. a-4b x I ?

Juliette [100K]

-3-4(5)
-4(5)=-20
-3-20
The answers is -23

8 0

3 years ago

Two liters of water are poured into an empty vase shaped like an octagonal prism. The base area is 100 square centimeters. What

Molodets [167]

Answer: Height of the water is 20 cm.

Step-by-step explanation:

Since we have given that

Base area = 100 square cm

volume of vase shaped like an octogonal prism = 2 liters

We need to find the height of water.

and 1 liter = 1000 cm³

2 liters = 2×1000 cm³

As we know the formula for "Volume":

$Volume=\text{Base Area}\times height\\\\2\times 1000=100\times height\\\\height=\dfrac{2000}{100}\\\\height=20\ cm$

Hence, height of the water is 20 cm.

4 0

3 years ago